我有一种 Material ,可以是热的或冷的,白色的或黑色的。状态可以是热和白、热和黑、冷和白、冷和黑。我有以下类(class)
class myMaterial
{
public:
enum state
{
DEFAULT = 0,
HOT = 1 << 0,
WHITE = 1 << 1
};
void SetState(int);
private:
int m_state;
};
void myMaterial::SetState(int state)
{
m_state = state;
}
现在在 main() 中,我调用 SetState 方法来设置这些状态
myMaterial material;
material.SetState(myMaterial::HOT);
下面的位运算是否正确,设置所有类型的状态
HOT and WHITE => myMaterial::HOT | myMaterial::WHITE
HOT and BLACK => myMaterial::HOT | ~myMaterial::WHITE
COLD and WHITE => ~myMaterial::HOT | myMaterial::WHITE
COLD and BLACK => ~myMaterial::HOT | ~myMaterial::WHITE
最佳答案
修改后,问题似乎有点不同,不再需要@adrin 的每个属性 2 位的解决方案。
现在只是:
HOT and WHITE = myMaterial::HOT | myMaterial::WHITE
HOT and BLACK = myMaterial::HOT
COLD and WHITE = myMaterial::WHITE
COLD and BLACK = 0
如果你添加一个额外的位来说明状态是否已知:
UNKNOWN = 0
HOT and WHITE = myMaterial::HOT | myMaterial::WHITE | myMaterial::KNOWN
HOT and BLACK = myMaterial::HOT | myMaterial::KNOWN
COLD and WHITE = myMaterial::WHITE | myMaterial::KNOWN
COLD and BLACK = myMaterial::KNOWN
关于c++ - 位掩码 : Set different states of an object via set method,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21379233/