c++ - 编写程序删除数组中的重复项

Question

我正在开发从数组中删除重复项的程序 我在这里使用了三个函数:一个用于获取输入，例如大小和数字，第二个函数用于删除重复项并返回没有重复项的数字，第三个函数只是一份报告显示了大小和新数字，但我遇到了问题，我不知道我在报告或 phillip erreur 中想到的步骤:

In function ‘int main()’: invalid conversion from ‘int*’ to ‘int’,initializing argument 1 of ‘void report(int, int)’

#include <iostream>
using namespace std;

const int size = 100;

void phillip(int[], int & );
/* Preconditions: Array of base type in declared and int varuable declared
   postconditions: the array is filled with values supllied by the user at
   the keybord. the user is assked how many values they want - this value is
   given to the second argument.
*/

int remdubs(int[], int noel);
/* Preconditions: An array of basetype int that  has noel values.
   postconditions: The number of unique elemts in the array is returned. The function removes all dubplicates inside the array.
*/

void report(int s, int d);

int main()
{
    int ruby[size];
    int numele, numuniq;

    phillip(ruby, numele);

    numuniq = remdubs(ruby, numele);

    report(ruby, numuniq);

    return 0;
}

void phillip(int[], int& )
{
    int s;
    cout << "\nHow many values you want? ";
    cin >> s;

    cout << "\nPlease input 10 integers, hitting return after each one \n";
    for (int i = 0; i < s; i++)
    {
        int num;
        cin >> num;
    }
}

int rembups(int sapphire[], int noel)
{
    for (int i = 0; i < noel; i++)
    {
        for (int j = i + 1; j < noel; j++)
        {

            if (sapphire[i] == sapphire[j])
            {
                for (int k = j; k < noel; k++)
                    sapphire[k] = sapphire[k + 1];

                noel--;

                j--;
            }
        }
    }
    return noel;
}

void report(int s, int d)
{
    cout << "\nYou entered " << s << "distinct numbers: " << d;
}

Answer 1

无法比您的错误更好地解释它:

void report (int s, int d);

这个函数要求两个整数值，你传递一个数组给它，随着功能的衰退，它的行为就像一个整数指针

int ruby[size];
report (ruby, numuniq);

我不确定你的程序的行为，但你应该做类似的事情

report(ruby[0], numuniq);

即:访问数组的元素并将其提供给函数