我正在尝试编写一个模板，用于从文件读取/向文件写入结构。
为了避免愚蠢的错误，我想保留一份读/写逻辑拷贝 - 而不是在两个单独的读/写函数中保留两份拷贝。
但截至目前，我收到了error C4430: missing type specifier - int assumed,
我在以下地方发表了评论:
struct VehicleInfo
{
int Model;
int WindowTint;
int Kit;
};
template <typename T> stream_perform(std::ofstream& stream, T& what)
{
stream.write(reinterpret_cast<char*>(&what), sizeof(T));
}//error on this line
template <typename T> stream_perform(std::ifstream& stream, T& what)
{
stream.read(reinterpret_cast<char*>(&what), sizeof(T));
}//error on this line
template <typename T> T& stream_op(T& stream, VehicleInfo& info)
{
stream_perform(stream, info.Model);//T int
stream_perform(stream, info.WindowTint);//T int
stream_perform(stream, info.Kit);//T int
//hundreds lines more of variables
return stream;
}
std::ofstream& operator<<(std::ofstream& stream, VehicleInfo& info)
{
return stream_op(stream, info);
}
std::ifstream& operator>>(std::ifstream& stream, VehicleInfo& info)
{
return stream_op(stream, info);
}
我想知道，编译器可以推导出所有类型，为什么它不能编译这个，它是否认为没有指定类型？
最佳答案
I'm wondering, the compiler can deduce all types so why can't it compile this and does it think that there is no type specified?
没有指定类型:
template <typename T> stream_perform(std::ofstream& stream, T& what)
^^^^
你需要里面的东西。我猜你打算写:
template <typename T> void stream_perform(std::ofstream& stream, T& what)
关于c++ - 使用流模板以避免复制代码会产生 "error C4430: missing type specifier - int assumed"，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/31601556/