标签 c++ overloading
<分区>
为什么我不能重载这两个函数？
#include <iostream>
using namespace std;
class Base
{
public:
void run(int a);
void run(const int a);
};
int main() {
// your code goes here
return 0;
}
输出:
prog.cpp:8:7: error: 'void Base::run(int)' cannot be overloaded
void run(const int a);
^
prog.cpp:7:7: error: with 'void Base::run(int)'
void run(int a);
最佳答案
根据标准:
13.1 Overloadable declarations
....(3.4) — Parameter declarations that differ only in the presence or absence of
constand/orvolatileare equivalent. That is, theconstandvolatiletype-specifiers for each parameter type are ignored when determining which function is being declared, defined, or called. [ Example:typedef const int cInt; int f (int); int f (const int); // redeclaration of f(int) int f (int) { /* ... */ } // definition of f(int) int f (cInt) { /* ... */ } // error: redefinition of f(int)—end example ]
Only the
constandvolatiletype-specifiers at the outermost level of the parameter type specification are ignored in this fashion;constandvolatiletype-specifiers buried within a parameter type specification are significant and can be used to distinguish overloaded function declarations. In particular, for any typeT, “pointer toT,” “pointer toconst T,” and “pointer tovolatile T” are considered distinct parameter types, as are “reference toT,” “reference toconst T,” and “reference tovolatile T.”
关于c++ - 为什么这两个函数不能重载呢？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/37896991/