我正在使用 C++ 客户端代码与 VB 应用程序交互。我在这方面完全是新手(我只是一名化学工程师),所以如果问题很愚蠢,请原谅。
因此,访问“BackDoor”接口(interface)需要 VB 中的以下代码,我可以获得所有其他接口(interface),因为我遵循层次结构(如 strm = hyApp.ActiveDocument.Flowsheet.Streams.Item(strmName)
但是正如您在下面的代码中看到的,BackDoor 接口(interface)等于 ProcessStream 接口(interface)!!我不明白这一点,也不知道如何在 C++ 中实现...你能帮忙吗?
VB 代码:
Function GetMassExergy(strmName As String) As Double
GetMassExergy = EmptyValue_enum.HEmpty 'initialize to empty
Dim strm As ProcessStream
Dim bd As BackDoor
Dim corrNamesVar As TextFlexVariable
Dim corrNames() As String
Dim i As Integer
Dim exergMoniker As String
Dim exerg As RealVariable
Dim Bval As Double
strm = hyApp.ActiveDocument.Flowsheet.Streams.Item(strmName)
bd = strm
corrNamesVar = bd.BackDoorTextVariable("HysysCorrelation.300.[]:Name.0").Variable
corrNames = corrNamesVar.Values
For i = 0 To corrNames.Count - 1
If corrNames(i) = "Mass Exergy" Then
Exit For
End If
Next i
If i = corrNames.Count Then
'failed to find Mass Exergy Correlation
Exit Function
End If
exergMoniker = String.Format("HysysCorrelation.300.{0}:ExtraData.550.0", i)
exerg = bd.BackDoorVariable(exergMoniker).Variable
Bval = exerg.GetValue("kJ/kg")
GetMassExergy = Bval
End Function
C++ 代码:
void ConnectToHYSYS::GetBackDoor() {
//HyStream is already acquired using Hierarchy
IDispatch* hyStream;
// Try to Query BackDoor from hyCase interface
HRESULT hr = hyStream->QueryInterface(__uuidof(hyBackDoor), (void**)&hyBackDoorDisp);
//Last hr returns S_OK
if (SUCCEEDED(hr))
{
cout << "Got the BackDoor safely" << endl;
//Get BackDoor Text Variable,
VARIANT result;
VariantInit(&result);
// Try to Get a property from BackDoor interface (to make sure that it returned //an actual interface)
hr = COMMethod(DISPATCH_PROPERTYGET, &result, hyBackDoorDisp, L"BackDoorTextVariable", 1, "HysysCorrelation.300.[]:Name.0");
CheckForHr(hr);
BackDoorTextVariable = result.pdispVal;
if (SUCCEEDED(hr))
{
cout << "Got the BackDoor Text Variable safely" << endl;
}
if (FAILED(hr)) {
cout << "Couldnt get the BackDoor Text Variable" << endl;
}
}
if (FAILED(hr)) {
cout << "Couldnt get the BackDoor" << endl;
}
}
以下是我用来访问接口(interface)内属性的 COMMethod(它可以与所有其他接口(interface)一起正常工作)
HRESULT ConnectToHYSYS::COMMethod(int nType, VARIANT * pvResult, IDispatch * pDisp, LPOLESTR ptName, int cArgs...)
{
if (!pDisp) return E_FAIL;
va_list marker;
va_start(marker, cArgs);
DISPPARAMS dp = { NULL, NULL, 0, 0 };
DISPID dispidNamed = DISPID_PROPERTYPUT;
DISPID dispID;
char szName[200];
// Convert down to ANSI
WideCharToMultiByte(CP_ACP, 0, ptName, -1, szName, 256, NULL, NULL);
// Get DISPID for name passed...
HRESULT hr = pDisp->GetIDsOfNames(IID_NULL, &ptName, 1, LOCALE_USER_DEFAULT, &dispID);
if (FAILED(hr)) {
return hr;
}
// Allocate memory for arguments...
VARIANT * pArgs = new VARIANT[cArgs + 1];
// Extract arguments...
for (int i = 0; i < cArgs; i++) {
pArgs[i] = va_arg(marker, VARIANT);
}
// Build DISPPARAMS
dp.cArgs = cArgs;
dp.rgvarg = pArgs;
// Handle special-case for property-puts!
if (nType & DISPATCH_PROPERTYPUT) {
dp.cNamedArgs = 1;
dp.rgdispidNamedArgs = &dispidNamed;
}
// Make the call!
hr = pDisp->Invoke(dispID, IID_NULL, LOCALE_SYSTEM_DEFAULT, nType, &dp, pvResult, NULL, NULL);
if (FAILED(hr)) {
return hr;
}
// End variable-argument section...
va_end(marker);
delete[] pArgs;
return hr;
}
我进行调用的行是唯一返回错误“0x80020008 错误变量类型”的行...我的意思是我在 COMMethod 中写的最后一小时行“hr = pDisp->Invoke(dispID, IID_NULL, LOCALE_SYSTEM_DEFAULT, nType, &dp, pvResult, NULL, NULL);"
最佳答案
您拥有的 VB 代码使用的是早期绑定(bind),而您拥有的 C++ 代码使用的是后期绑定(bind)。
将您的 C++ 代码切换为与 VB 代码类似的代码,例如:
void ConnectToHYSYS::GetBackDoor() {
IDispatch* hyStream = ...;
// Use an actual hyBackDoor
hyBackDoor* hyBackDoorDisp;
HRESULT hr = hyStream->QueryInterface(IID_PPV_ARGS(&hyBackDoorDisp));
if (SUCCEEDED(hr)) {
cout << "Got the BackDoor safely" << endl;
// From the VB code, it seems BackDoorTextVariable is a TextFlexVariable
hr = hyBackDoorDisp->get_BackDoorTextVariable(&BackDoorTextVariable);
CheckForHr(hr);
if (SUCCEEDED(hr)) {
cout << "Got the BackDoor Text Variable safely" << endl;
}
if (FAILED(hr)) {
cout << "Couldnt get the BackDoor Text Variable" << endl;
}
}
if (FAILED(hr)) {
cout << "Couldnt get the BackDoor" << endl;
}
}
您获得的调度对象不起作用的原因是通常只有第一个接口(interface)由标准调度程序处理。即使对于处理多个接口(interface)的自定义或手动调度程序,它们通常也不会调度隐藏(或以其他方式供私有(private)使用)接口(interface)。
关于c++ - 如何在没有返回它的属性/函数的情况下获取派生接口(interface) (OLE/COM),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40837201/