亲爱的读者
我正在为进程调度程序制作一个库模块。默认情况下,调度程序有 8 个条目 0..7,调度程序中的函数/进程使用函数指针调用。作为普通 C 程序编写,它按预期工作。但是现在我想在 .h 文件中配置函数指针我有指向函数指针的编译器错误。
我在 proclist[8] 中位于 &scheduler::dummy 的函数指针有问题,它们会给我带来错误,我不知道如何解决它们。
Can some one advice me what to do.
产品的错误是
scheduler.cpp:9: In file included from
Error compiling libraries
scheduler.h: 56:87: error:
cannot convert 'void (scheduler::*)(uint8_t*) {aka void (scheduler::*)(unsigned char*)}' to 'void (*)(uint8_t*) {aka void (*)(unsigned char*)}' in initialization
{ 7, 3900 ,10000 ,0,PROC_ACT ,&scheduler*: dummy7 , &proclist[7].val ,65 ,1}};
\\process table entry 7
Build failed for project 'Scheduler'
并且是这个错误的 7 倍。
scheduler.h: 56:87: error:
cannot convert 'void (scheduler::*)(uint8_t*) {aka void (scheduler::*)(unsigned char*)}' to 'void (*)(uint8_t*) {aka void (*)(unsigned char*)}' in initialization
.h文件中的代码如下
(第 56 行在代码块中指示)
//process structure
typedef struct process_t{ // Start of the Process scheduler structure
uint8_t index ; // index of this process in the process structure array
uint32_t starttime ; // Absolute start and next call time of the function
uint32_t delta ; // Time between the function to be called
uint32_t exetime ; // Time it takes to execute the function
uint8_t stat ; // skip, delete, change, active
void (*pt2function)(uint8_t*) ;// Pointer to function to be called
uint8_t *valptr ; // Pointer to value given as function Parameter
uint8_t val ; // Default value being pointed at
uint8_t nextprocess ; // Index to next process in the process structure array
};
class scheduler {
public:
void run();
void man (uint8_t *);
void dummy(uint8_t *);
// Processes 0,1..5 arrays of Process structs.
process_t proclist[8] = {{0, ROLLOFFSET ,0 ,0,PROC_ACT ,&scheduler::man , &proclist[0].val ,INIT ,1} , //Initialise(), Run ones in the process list
{ 1, 3000 ,2237 ,0,PROC_ACT ,&scheduler::dummy , &proclist[1].val ,65 ,2} , //process table entry 1
{ 2, 3100 ,2718 ,0,PROC_ACT ,&scheduler::dummy , &proclist[2].val ,66 ,3} , //process table entry 2
{ 3, 3200 ,3141 ,0,PROC_ACT ,&scheduler::dummy , &proclist[3].val ,67 ,4} , //process table entry 3
{ 4, 3300 ,2237 ,0,PROC_SKP ,&scheduler::dummy , &proclist[4].val ,65 ,5} , //process table entry 4
{ 5, 3400 ,2718 ,0,PROC_SKP ,&scheduler::dummy , &proclist[5].val ,66 ,6} , //process table entry 5
{ 6, 3500 ,3141 ,0,PROC_SKP ,&scheduler::dummy , &proclist[6].val ,67 ,7} , //process table entry 6
/*===Line 56 ==>*/ { 7, 3900 ,10000 ,0,PROC_ACT ,&scheduler::dummy , &proclist[7].val ,65 ,1}}; //process table entry 7
// and other functions if needed
private:
int8_t n, cnt;
uint32_t mmillis();
};
最佳答案
非静态成员函数有一个指向类实例的隐藏指针this
,所以Pointers to Member Functions需要一个对象,您不能像普通函数指针那样使用它们。
根据您的设计,您可以相互
使方法静态化:
static void man (uint8_t *); static void dummy(uint8_t *);
也许您必须再添加一个参数来传递对
scheduler
或process_t
实例的引用。或将
pt2function
更改为指向成员函数的指针:class scheduler; //process structure struct process_t{ // Start of the Process scheduler structure // ... void (scheduler::*pt2function)(uint8_t*) ;// Pointer to function to be called // ...
您以后可以像这样从
scheduler
使用这些指向成员函数的指针:class scheduler { // ... void run() { (this->*proclist[0].pt2function)(proclist[0].valptr); }
关于c++ - 指向类成员的函数指针生成编译器错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48699960/