c++ - 使用对象指针时如何访问成员函数

Question

我试图通过 nodePtr 访问值 Node，但遇到了问题。

//main//

Node n1 (true);
Node n2 (false);

Node *nPtr1 = &n1;
Node *nPtr2 = nPtr1;

cout << "Memory Locations: " << endl <<
  "\tn1: " << &n1 << endl <<
  "\tn2: " << &n2 << endl;

cout << "Pointer Info: " << endl <<
  "\tnPtr1: " << endl <<
  "\t\tMemory Address: " << &nPtr1 << endl <<
  "\t\tPoints to: " << nPtr1 << endl <<
  "\t\tValue of Pointee: " << nPtr1->GetValue() << endl <<
  endl <<
  "\tnPtr2: " << endl <<
  "\t\tMemory Address: " << &nPtr2 << endl <<
  "\t\tPoints to: " << nPtr2 << endl <<
  "\t\tValue of Pointee: " << nPtr2->GetValue() << endl <<
  endl;



//Node.cpp//

Node::Node(){
  m_next = nullptr;
}

Node::Node(bool value){
  m_value = value;
  m_next = nullptr;
}

void Node::ReplaceValue(){
  m_value = !m_value;
}

void Node::SetNext(Node* next){
  m_next = next;
}

Node* Node::GetNext(){
  return m_next;
}
bool Node::GetValue(){
  return m_value;
}

Node::~Node(){
}

当我运行这段代码时，我得到了:

Memory Locations:
        n1: 0x7ffd33aee010
        n2: 0x7ffd33aee000
Pointer Info:
        nPtr1:
                Memory Address: 0x7ffd33aedfe8
                Points to: 0x7ffd33aee010
                Value of Pointee: 1

        nPtr2:
                Memory Address: 0x7ffd33aedfe0
                Points to: 0x7ffd33aee010
                Value of Pointee: 1

但是 Value of Pointee 的预期输出应该反射(reflect)节点初始化时使用的 bool 值。

---

我尝试过使用 *nPtr2->GetValue() 和 *nPtr2.GetValue()，但这两种方法都会导致语法错误。

通过指针访问这些成员函数的正确方法是什么？如果我正确访问它们，那么为什么节点的值与预期不匹配？

Answer 1

Node *nPtr1 = &n1;
Node *nPtr2 = nPtr1;

当然，您在记录 m_value 字段时会得到相同的结果。 :) 您甚至可以在日志中看到它们都指向同一个实例。