C++和多指针

Question

我有一个关于指针的简单问题。这是我的代码:

#include <iostream>
#include <vector>

using namespace std;

int main()
{
    typedef float RtPoint[3]; 
    RtPoint** b = new RtPoint*[4];
    b[0] = (RtPoint*)new RtPoint;
    RtPoint* p = b[0];
    RtPoint c;
    (*p)[0] = &(c[0]);
    (*p)[1] = &(c[1]);
    (*p)[2] = &(c[2]);
    std::cout << p[1] << " " << &(c[0]) << std::endl;
    delete[] b;

    return 0;
}

所以我只想把 p[0], p[1] 和 p[2] 的地址c[0]、c[1] 和 c[2]。我的代码是错误的，但我没有找到解决方案。

---

对不起我的错这个代码有效:)

  typedef float RtPoint[3]; 
  RtPoint** b = new RtPoint*[4];
  b[0] = (RtPoint*)new RtPoint;
  RtPoint c;
  b[0] = &c;

编辑:是的，我看到了我的错误

Answer 1

如果您正在使用 C++，请忘记原始指针，并使用 std::vector。

但如果你真的坚持:

#include <iostream>
#include <vector>
using namespace std;

int main()
{
    typedef float RtPoint[3];
    RtPoint** b = new RtPoint*[4];
    b[0] = (RtPoint*)new RtPoint;
    RtPoint* p = b[0];
    RtPoint c;
    (*p)[0] = c[0];
    (*p)[1] = c[1];
    (*p)[2] = c[2];
    std::cout << p[1] << " " << &(c[0]) << std::endl;
    delete[] b;
}

顺便说一句，你没有初始化任何变量。