我有以下 payments_2015 表:
ref-no |Jan |Feb |Mar |Apr |May |Jun
1 | |PAID |PAID | |PAID |
2 | |PAID | | | |PAID
3 |PAID | |PAID |PAID |PAID |PAID
4 |PAID |PAID | |PAID |PAID |
5 |PAID | |PAID | | |
6 | | | | | |PAID
我正在使用以下查询检查每个 ref_no 有多少个月没有支付:
for(int i = 0; i < all_refNo_list.size(); i++) {
qryTxt = "INSERT INTO late_payments "
"select ref_no AS ref_no, sum(i_count) as unpaid_count from ("
"SELECT ref_no, CASE WHEN January = 'PAID' THEN 0 ELSE 1 END AS i_count, 1 AS month_no FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN February = 'PAID' THEN 0 ELSE 1 END , 2 FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN March = 'PAID' THEN 0 ELSE 1 END , 3 FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN April = 'PAID' THEN 0 ELSE 1 END , 4 FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN May = 'PAID' THEN 0 ELSE 1 END , 5 FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN June = 'PAID' THEN 0 ELSE 1 END , 6 FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN July = 'PAID' THEN 0 ELSE 1 END , 7 FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN August = 'PAID' THEN 0 ELSE 1 END , 8 FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN September = 'PAID' THEN 0 ELSE 1 END , 9 FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN October = 'PAID' THEN 0 ELSE 1 END , 10 FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN November = 'PAID' THEN 0 ELSE 1 END , 11 FROM payments_" + getCurrentYear() +
" UNION SELECT ref_no, CASE WHEN December = 'PAID' THEN 0 ELSE 1 END , 12 FROM payments_" + getCurrentYear() +
") A Where ref_no = " + all_refNo_list[i];
query.prepare(qryTxt);
if (!query.exec())
{
qDebug() << "Error" << query.lastError().text();
}
}
结果是下面的 late_payments
表:
ref_no |unpaid_count
1 |3
2 |4
3 |1
4 |2
5 |4
6 |5
现在,如果我在 1 月为 ref_no = 1 插入“PAID”,结果仍然相同。当然它会保持不变,因为我正在插入已经存在的记录而不是更新。
每当某个月针对特定“ref_no”被选中为“PAID”时,我都无法更新这些值。即:只要有变化就更新表。
更新:
我试过以下方法:
for(int i = 0; i < getAllRefNoList().size(); i++) {
qryTxt = "UPDATE late_payments "
"SET unpaid_count = ("
"select sum(i_count) as unpaid_count from ("
"SELECT CASE WHEN January = 'PAID' THEN 0 ELSE 1 END AS i_count, 1 AS month_no FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN February = 'PAID' THEN 0 ELSE 1 END , 2 FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN March = 'PAID' THEN 0 ELSE 1 END , 3 FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN April = 'PAID' THEN 0 ELSE 1 END , 4 FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN May = 'PAID' THEN 0 ELSE 1 END , 5 FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN June = 'PAID' THEN 0 ELSE 1 END , 6 FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN July = 'PAID' THEN 0 ELSE 1 END , 7 FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN August = 'PAID' THEN 0 ELSE 1 END , 8 FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN September = 'PAID' THEN 0 ELSE 1 END , 9 FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN October = 'PAID' THEN 0 ELSE 1 END , 10 FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN November = 'PAID' THEN 0 ELSE 1 END , 11 FROM payments_" + getCurrentYear() +
" UNION SELECT CASE WHEN December = 'PAID' THEN 0 ELSE 1 END , 12 FROM payments_" + getCurrentYear() +
") A WHERE ref_no = " + getAllRefNoList()[i] + ")";
query.prepare(qryTxt);
if (!query.exec())
{
qDebug() << "Error" << query.lastError().text();
}
但是没有成功..
附注:我正在 Qt 上为一个 c++ 应用程序实现这些选择语句。我正在使用 QSqlQueryModel
在 QTableView
上显示选择语句的结果。
最佳答案
首先,创建一个查询来计算所需的表:
SELECT refno,
(ifnull(Jan, '') != 'PAID') +
(ifnull(Feb, '') != 'PAID') +
...
(ifnull(Dec, '') != 'PAID) AS unpaid_count
FROM payments_2015;
然后您可以删除该表,而是使用动态生成这些结果的 View :
CREATE VIEW late_payments_2015 AS
SELECT ...;
关于c++ - SQLITE:如何在 UPDATE 语句中使用 SELECT 语句更新表?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34483499/