c++ - 条件语句简化 - C++

Question

在这段代码中减少我的条件的最佳方法是什么，是简单地实现用于字符串比较的 Boost 库还是有其他方法？如果可能的话，我更愿意避免使用 boost。

上述问题如何在以下代码中实现？

cout << " Please Enter An Answer Of Yes(Y) or No(N):";
string question; cin >> question;

if (question == "yes" || question == "Yes" || question == "Y" || question == "y" || question == "YEs" || question == "YES" || question == "yeS" || question == "yES") 
{
    cout << "You said yes!" << endl;
    return 1;
} 
else if (question == "No" || question == "NO" || question == "nO" || question == "N" || question == "n")
{
    cout << "You said no!" <<endl;
    return 0;
}  
else 
{
    AskAQuestion();
}

Answer 1

这可能不是最有效的解决方案，但如果您将整个字符串转换为小写，那么您只需要检查单词和字母而不是所有可能的排列。所以如果你有

void make_lowercase(std::string& data)
{
    std::transform(data.begin(), data.end(), data.begin(), ::tolower);
}

然后

cout << " Please Enter An Answer Of Yes(Y) or No(N):";
string question; cin >> question;

if (question == "yes" || question == "Yes" || question == "Y" || question == "y" || question == "YEs" || question == "YES" || question == "yeS" || question == "yES") 
//...

成为

cout << " Please Enter An Answer Of Yes(Y) or No(N):";
string question; 
cin >> question;
make_lowercase(question);

if (question == "yes" || question == "y")
//...