我已经可以做到了:
struct {
uint64 _i;
bool operator()(uint64 elem)
{
const uint64 i = _i++; return elem & i; // Just an example
}
} filter;
// Templated function
Array<uint64> clone = Containers::filter(array, filter);
我想知道是否可以在函数调用中移动结构定义,这样我就可以定义一个像这样的宏:
Array<uint64> clone = Containers::filter(array, ENUMERATE(i, elem, elem & i)); // Same as above
当我尝试这个时,我得到了 expected primary-expression before 'struct'
:
Array<uint64> clone = Containers::filter(array, struct {
uint64 _i;
bool operator()(uint64 elem)
{
const uint64 i = _i++; return elem & i;
}
});
最佳答案
有状态的、可变的 lambda 可以满足您的要求:
Array<uint64> clone = Containers::filter(
array,
[_i = uint64{0}](uint64 elem) mutable -> bool {
const uint64 i = _i++;
return elem & i;
}
);
关于c++ - 在函数调用中定义一个匿名结构,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53554465/