我试图找到一种更有效的方法来将 uint8_t 字节的可变长度数组加载到 std::queue
以下代码片段试图将实际代码简化为更有用的示例;如果它过于复杂,请原谅我。
代码片段有效,但我无法确定 std::queue 的每个元素的实际长度,而它们仍在队列的前面。我的问题是,“有没有什么方法可以将指向无符号字节数组的指针插入队列,而无需创建本地数组、将传递的参数复制到其中然后将本地指针插入队列的中间步骤(请参阅代码中的注释)?
#include <queue>
#include <string>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
using namespace std;
std::queue<uint8_t*> _q;
void routineSubroutine(uint8_t array_a[], int size_a)
{
/*
* Is there anyway to push the uint8 array_a into the queue (_q) without
* creating a new pointer to a byte array, copying the passed
* argument into it and the pushing it?
*/
uint8_t* a = new uint8_t[size_a];
memcpy((void*) a, (const void*) array_a, size_a);
_q.push(a);
}
int main(int argc, char** argv)
{
uint8_t myArray[512];
char cfa[] = {"I wish I was at Chick-Fil-A right now"};
memset((void*) myArray, 0x00, sizeof (myArray));
memcpy((void*) myArray, (const void*) cfa, strlen(cfa));
routineSubroutine(myArray, strlen(cfa));
char five[] = {"Five Guys will do in a pinch"};
memcpy((void*) myArray, (const void*) five, strlen(five));
routineSubroutine(myArray, strlen(five));
while (_q.size() > 0)
{
printf("Queue string value = %s\n", (char*) _q.front());
/*
* How do I go about determining the number of bytes in the uint8_t
* array, whose address is at the front of the queue?
*/
_q.pop();
}
return 0;
}
最佳答案
The code snippet works, with the exception of my inability to determine the actual length of each of the elements of the std::queue while they are still at the front of the queue
使用知道其长度/大小的适当容器并调用适当的成员函数。单纯的指针做不到这一点。
以下是您使用 std::vector
重写的代码示例:
#include <queue>
#include <string>
#include <vector>
#include <iostream>
std::queue<std::vector<uint8_t>> _q;
void routineSubroutine(const std::vector<uint8_t>& a)
{
_q.push(a);
}
int main(int argc, char** argv)
{
char cfa[] = {"I wish I was at Chick-Fil-A right now"};
routineSubroutine({std::begin(cfa), std::end(cfa)}); // creates a temp uint8_t vector
char five[] = {"Five Guys will do in a pinch"};
routineSubroutine({std::begin(five), std::end(five)}); // creates a temp uint8_t vector
while ( !_q.empty() )
{
// use the `write()` function to control the number of characters
std::cout.write(reinterpret_cast<const char *>(_q.front().data()), _q.front().size());
std::cout << "\n";
_q.pop();
}
return 0;
}
输出:
I wish I was at Chick-Fil-A right now
Five Guys will do in a pinch
关于c++ - 使用元素加载 std::queue<uint8_t*> 的更有效方法?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56908778/