<分区>
让我们假设下面的类 Foo。
struct Foo
{
int i;
bool j;
};
为什么我从以下几行中得到不同的结果？
int main(void)
{
//I thought the default constructor would be called
Foo foo1;
cout << foo1.i << " : " << foo1.j << endl; // " 4196352 : 0 " --> ctor not called?
//if calling the default constructor explicitly
foo1 = Foo();
cout << foo1.i << " : " << foo1.j << endl; // " 0 : 0" --> ctor called.
}
难道不应该隐式调用默认构造函数吗？
根据 cpp reference :
If no user-declared constructors of any kind are provided for a class type (struct, class, or union), the compiler will always declare a default constructor as an inline public member of its class.