我有两个相交的圆,我想让相交区域有颜色,即使这两个圆是透明的。我以为我可以找到一些方法来使用 css mix-blend-mode
属性来做到这一点,但我没有成功。
当然,我可以让圆圈有颜色并降低它们的不透明度,但我希望它们是白色或透明的,只有重叠区域才会有背景色。
我希望交叉区域能够动态变化,因为一个圆圈会跟随鼠标。 这是 codepen为此。
我不确定从哪里开始,如果 css 有一些技术,或者是否必须使用 jquery 来完成。
$(document).mousemove(function(e) {
$('.cursor').eq(0).css({
left: e.pageX - 25,
top: e.pageY - 20
});
// circles
var c1 = $('.cursor');
var c2 = $('.circle');
// radius
var d1 = c1.outerWidth(true)/2;
var d2 = c2.outerWidth(true)/2;
// centers of first circle
var x1 = c1.offset().left + c1.width()/2;
var y1 = c1.offset().top + c1.height()/2;
// centers of second circle
var x2 = c2.offset().left + c2.width()/2;
var y2 = c2.offset().top + c2.height()/2;
var i1 = c2.find('.inter1');
var i2 = c2.find('.inter2');
var o = c1.find('.overlap');
function calc() {
var a = d2;
var b = d1;
var c = Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
var d = (b*b+c*c-a*a)/(2*c);
var h = Math.sqrt((b*b) - (d*d));
if (d < 0 || $.isNumeric(h)) {
c2.css('border-color', 'red');
} else {
c2.css('border-color', 'black');
}
var x3 = (x2-x1)*d/c + (y2-y1)*h/c + x1;
var y3 = (y2-y1)*d/c - (x2-x1)*h/c + y1;
var x4 = (x2-x1)*d/c - (y2-y1)*h/c + x1;
var y4 = (y2-y1)*d/c + (x2-x1)*h/c + y1;
if ($.isNumeric(h)) {
i1.show();
i2.show();
} else {
i1.hide();
i2.hide();
}
i1.offset({ top: y3-5, left: x3-5});
i2.offset({ top: y4-5, left: x4-5});
} calc();
});
body {
background: #fff;
}
.overlap {
position: absolute;
top: 0;
right: 0;
bottom: 0;
left: 0;
background: rgba(0, 0, 0, 0.5);
}
.cursor {
height: 50px;
width: 50px;
border-radius: 50%;
position: absolute;
pointer-events: none;
z-index: 999;
border: 1px solid black;
outline: 1px solid #c9d3ff;
overflow: none;
}
.circle {
border-radius: 50%;
position: absolute;
top: 50%;
left: 50%;
transform: translate(-50%, -50%);
width: 200px;
height: 200px;
border: 1px solid black;
outline: 1px solid #c9d3ff;
}
.circle::after,
.cursor::after {
display: block;
content: '';
height: 1px;
background: #c9d3ff;
position: absolute;
top: 50%;
left: 0;
right: 0;
}
.circle::before,
.cursor::before {
display: block;
content: '';
width: 1px;
background: #c9d3ff;
position: absolute;
left: 50%;
top: 0;
bottom: 0;
}
.inter {
width: 10px;
height: 10px;
background: black;
border-radius: 50%;
position: absolute;
display: none;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="cursor">
</div>
<div class="circle">
<div class="inter1 inter"></div>
<div class="inter2 inter"></div>
<div>
最佳答案
解决此问题的一种方法是在主圆圈内添加一个“内部光标”圆圈。基于鼠标的移动,它会随着主光标一起移动,从而产生重叠的错觉。
在这种情况下,相交圆的背景颜色无关紧要。此外,您不必担心混合混合模式,因为内部光标具有背景颜色并且是隐藏的。仅当鼠标悬停在主圆上时才能查看。
看这个例子:
$(document).mousemove(function(e) {
// elements
let cursor = $('.cursor');
let innerCursor = $('.inner-cursor');
let c2 = $('.circle');
let pos = {
left: e.pageX - 25,
top: e.pageY - 20
};
cursor.css(pos);
innerCursor.css({
left: pos.left - c2.offset().left,
top: pos.top - c2.offset().top
});
// circles
// radius
var d1 = cursor.outerWidth(true) / 2;
var d2 = c2.outerWidth(true) / 2;
// centers of first circle
var x1 = cursor.offset().left + cursor.width() / 2;
var y1 = cursor.offset().top + cursor.height() / 2;
// centers of second circle
var x2 = c2.offset().left + c2.width() / 2;
var y2 = c2.offset().top + c2.height() / 2;
var i1 = c2.find('.inter1');
var i2 = c2.find('.inter2');
var o = cursor.find('.overlap');
function calc() {
var a = d2;
var b = d1;
var c = Math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2));
var d = (b * b + c * c - a * a) / (2 * c);
var h = Math.sqrt((b * b) - (d * d));
// console.log(a, b, c, d, h);
if (d < 0 || $.isNumeric(h)) {
c2.css('border-color', 'red');
} else {
c2.css('border-color', 'black');
}
var x3 = (x2 - x1) * d / c + (y2 - y1) * h / c + x1;
var y3 = (y2 - y1) * d / c - (x2 - x1) * h / c + y1;
var x4 = (x2 - x1) * d / c - (y2 - y1) * h / c + x1;
var y4 = (y2 - y1) * d / c + (x2 - x1) * h / c + y1;
if ($.isNumeric(h)) {
i1.show();
i2.show();
} else {
i1.hide();
i2.hide();
}
i1.offset({
top: y3 - 5,
left: x3 - 5
});
i2.offset({
top: y4 - 5,
left: x4 - 5
});
}
calc();
});
body {
background: #fff;
}
.clip {
display: inline-block;
background: blue;
height: 50px;
width: 50px;
border-radius: 50%;
clip-path: ellipse(50px 50px at 50% 0%);
position: absolute;
left: 750px;
top: 40px;
}
.cursor {
left: 750px;
top: 40px;
}
.cursor {
height: 50px;
width: 50px;
border-radius: 50%;
position: absolute;
pointer-events: none;
z-index: 999;
border: 1px solid black;
outline: 1px solid #c9d3ff;
overflow: none;
mix-blend-mode: multiply;
background: rgba(100, 100, 100, 0.1);
}
.circle {
background: rgba(100, 100, 100, 0.1);
border-radius: 50%;
position: absolute;
top: 50%;
left: 50%;
transform: translate(-50%, -50%);
width: 200px;
height: 200px;
border: 1px solid black;
outline: 1px solid #c9d3ff;
overflow: hidden;
}
.circle::after,
.cursor::after {
display: block;
content: '';
height: 1px;
background: #c9d3ff;
position: absolute;
top: 50%;
left: 0;
right: 0;
}
.circle::before,
.cursor::before {
display: block;
content: '';
width: 1px;
background: #c9d3ff;
position: absolute;
left: 50%;
top: 0;
bottom: 0;
}
.inter {
width: 10px;
height: 10px;
background: black;
border-radius: 50%;
position: absolute;
display: none;
}
.inner-cursor {
height: 50px;
width: 50px;
border-radius: 50%;
position: absolute;
pointer-events: none;
background: green;
left: 50%;
top: 50%;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="cursor">
</div>
<span class="clip"></span>
<div class="circle">
<div class='inner-cursor'></div>
<div class="inter1 inter"></div>
<div class="inter2 inter"></div>
</div>
关于javascript - 填充重叠的圆形区域,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57665335/