c++ - 为什么我的代码对于形状 "rectangle"处于无限循环中？

Question

这是代码

#include <iostream>
#include <string>
using namespace std;

void printTriangles(){
int length;
int width;
int base;
}


void printRectangles(){
int length;
int width;
int base;
string shape;
string repeat;
if ("rectangle" == shape)
{
    cout << "Enter the length of the rectangle: ";
    cin >> length;
    cout << endl;
    cout << "Enter the width of the rectangle: ";
    cin >> width;
}
if ("Rectangle" == shape)
{
    cout << "Enter the length of the rectangle: ";
    cin >> length;
    cout << endl;
    cout << "Enter the width of the rectangle: ";
    cin >> width;
}
for (int row = 1; row <= width; row++)
{
    for (int col = 1; col <= length; col++)
    {
        cout << "*";
    }
    cout << endl;
}

}
void printSquares(){
int length;
int width;
int base;
}


int main ()
{
int length;
int width;
int base;
string shape;
string repeat;

cout << "I will print squares for you!"<< endl << "Rectangles and triangles, too!"<< endl << endl;

cout << "Enter the shape that you would like to print (rectangle, triangle,  or square): ";
cin >> shape;

if ("rectangle" == shape)
printRectangles();
return 0;
}

当我输入 Rectangle 时，代码进入无限循环的星号，过去一天我一直在处理这个问题，但我还没有弄清楚我做错了什么。我相信我称我为“printRectangles();”功能正常，有人可以告诉我我是否正确调用了它。

Answer 1

在使用它们的值之前一定要初始化非静态局部变量。

试试这个:

void printRectangles(){
    int length = 0; // initialize for in case the reading fails
    int width = 0;

    // This is a function for printing rectangle,
    // so no checking for "rectangle", which is impossible because the input is not passed here

    cout << "Enter the length of the rectangle: ";
    cin >> length;
    cout << endl;
    cout << "Enter the width of the rectangle: ";
    cin >> width;
    for (int row = 1; row <= width; row++)
    {
        for (int col = 1; col <= length; col++)
        {
            cout << "*";
        }
        cout << endl;
    }

}