c++ - 如何让类在没有 getter 的情况下返回其他类型？

Question

我的代码:

class MyWindowSettings {

public:

    const ofGLFWWindowSettings& get(){
        return settings;
    }

private:
    ofGLFWWindowSettings settings;
};

如果没有 getter，我如何将此类用于需要 ofGLFWWindowSettings 而不是 MyWindowSettings 的函数？

我现在是

MyWindowSettings settings;
ofCreateWindow(settings.get());

但我想像下面那样做

MyWindowSettings settings;
ofCreateWindow(settings);

我该怎么做？

Answer 1

您可能要做的是使用 user-defined convertion运算符(operator)

class MyWindowSettings {

public:

    operator const ofGLFWWindowSettings&(){
        return settings;
    }

private:
    ofGLFWWindowSettings settings;
};