c++ - gmock - 如何使用 noexcept 说明符模拟函数

Question

我需要模拟以下函数:

 virtual void fun() noexcept = 0;

是否可以使用 gmock ？

Gmock 有以下宏:#define GMOCK_METHOD0_(tn, constness, ct, Method, ...) 但有注释://INTERNAL IMPLEMENTATION - DON'T USE在用户代码中!!! 此外，我不知道如何使用该宏(参数 tn 和 ct 的含义)？

编辑

以下模拟:

GMOCK_METHOD0_(, noexcept, ,fun, void());

使用 gmock 1.7.0 编译但是当我使用 gmock 1.8.1 编译它时出现编译错误:

main.cpp:17: error: expected identifier before ‘noexcept’
 GMOCK_METHOD0_(, noexcept, ,fun, void());
                  ^
gmock-generated-function-mockers.h:153: in definition of macro ‘GMOCK_METHOD0_’
   constness ::testing::internal::Function<__VA_ARGS__>* ) const { \
   ^
main.cpp:17: error: expected ‘,’ or ‘...’ before ‘noexcept’
 GMOCK_METHOD0_(, noexcept, ,fun, void());
                  ^
gmock-generated-function-mockers.h:153: in definition of macro ‘GMOCK_METHOD0_’
   constness ::testing::internal::Function<__VA_ARGS__>* ) const { \
   ^
main.cpp:-1: In member function ‘testing::internal::MockSpec<void()> MockX::gmock_fun(const testing::internal::WithoutMatchers&, int) const’:

gmock-generated-function-mockers.h:154: error: ‘AdjustConstness_noexcept’ is not a member of ‘testing::internal’
     return ::testing::internal::AdjustConstness_##constness(this)-> \
            ^
main.cpp:17: in expansion of macro ‘GMOCK_METHOD0_’
 GMOCK_METHOD0_(, noexcept, ,fun, void());
 ^

Answer 1

现在这是可能的，因为 v1.10.0 有了新的语法。 见change log和 new syntax explanation

新语法包含一个单独的参数规范来传递限定符

class MyMock {
   public:
      MOCK_METHOD(ReturnType, MethodName, (Args...), (Specs...));
};