我正在为我的 C++ 类做家庭作业，但我在重载构造函数方面遇到了困难。默认构造函数工作正常，但重载构造函数将无法正常工作。任何指导都会被应用。
/*
Name:Isis Curiel
Date:04/05/2017
Assignment 10
Instructions:
Redo assignment 5 by
1. Defining a class Date that has
(1) Three member variables:
date,
month,
year
(2) member functions
constructor: Initializes the Date to the given month, day and
year or to the default value. you can overload the constructor,
or use default arguments.
example use:
Date today(3,31, 2017); // 03/31/2017
Date firstDay; // will be 01/01/2017
reset: reset the month, day and year based on the parameters. So today.reset(4,1,2017); will change today to 04/01/2017.
get_day_of_week: return the day of the week as int 0-6
get_day_of_week_name: return the day of the week as a string
print: print out the date information include the date, month, year, day of the week.
(3) helper funcions:
bool is_leap_year();
// Returns true if the given year is a leap year
int get_century_value();
// Returns a value computed from the century of the year
int get_year_value();
// Returns a value computed based on the years since the beginning of the century.
int get_month_value();
// Returns a value (from a table) for the Date's month
2. write a main function to test the class.
*/
#include "stdafx.h"
#include <iostream>
#include <string>
#include <windows.h>
using namespace std;
class Date {
private:
int date, month, year, newDate, newMonth, newYear;
/*
reset: reset the month, day and year based on the parameters. So today.reset(4,1,2017); will change today to 04/01/2017.
get_day_of_week: return the day of the week as int 0-6
get_day_of_week_name: return the day of the week as a string
print: print out the date information include the date, month, year, day of the week.
*/
public:
Date() {
month = 01;
date = 01;
year = 2017;
}
Date(int fmonth, int fdate, int fyear) {
fmonth = month;
fdate = date;
fyear = year;
}
bool is_leap_year(int year) {
if (((year % 4 == 0) && (!(year % 100 == 0))) || ((year % 400 == 0)))
{
////isLeapYear = true;
return true;
}
else
return false;
}
int get_century_value(int year) {
int centValue;
year = year / 100;
year = year % 4;
year = 3 - year;
year = year * 2;
centValue = year;
return centValue;
}
int get_year_value(int year) {
int y1;
int yearVal;
year = year % 100;
y1 = year / 4;
yearVal = y1 + year;
return yearVal;
}
int get_month_value(int month, int year) {
if (month == 1 && is_leap_year(year) == false)
return 0; ///but doesnt returning 0 cause issues ?
else if (month == 1 && is_leap_year(year))
return 6;
else if (month == 2 && is_leap_year(year) == false)
return 3;
else if (month == 2 && is_leap_year(year))
return 2;
else if (month == 3)
return 3;
else if (month == 4)
return 6;
else if (month == 5)
return 1;
else if (month == 6)
return 4;
else if (month == 7)
return 6;
else if (month == 8)
return 2;
else if (month == 9)
return 5;
else if (month == 10)
return 0;
else if (month == 11)
return 3;
else if (month == 12)
return 5;
else
return 6;
}
int get_day_of_week(int month, int date, int year) {
int x;
x = ((date + get_month_value(month, year) + get_year_value(year) + get_century_value(year)) % 7);
///((getMonthValue + getYearValue + getCenturyValue)%7)
return x;
}
void get_day_of_week_name(int month, int date, int year) {
if (month > 12 || month < 1) {
cout << "Try again Please enter a month, day, and year, separated by " <<
"spaces(e.g., '7 4 2008') : ";
get_day_of_week(month, date, year);
cin >> month;
cin >> date;
cin >> year;
}
else if (month == 2 && date == 29 && is_leap_year(year) == false)
{
cout << "Try again Please enter a month, day, and year, separated by " <<
"spaces(e.g., '7 4 2008') : ";
get_day_of_week(month, date, year);
cin >> month;
cin >> date;
cin >> year;
}
else if (date > 31 || date < 1) {
cout << "Try again Please enter a month, day, and year, separated by " <<
"spaces(e.g., '7 4 2008') : ";
get_day_of_week(month, date, year);
cin >> month;
cin >> date;
cin >> year;
}
else if (month == 4 || month == 7 || month == 9 || month == 11 && date > 30) {
cout << "Try again Please enter a month, day, and year, separated by " <<
"spaces(e.g., '7 4 2008') : ";
get_day_of_week(month, date, year);
cin >> month;
cin >> date;
cin >> year;
}
else {
string dayW;
if (get_day_of_week(month, date, year) == 0)
dayW = "Sunday";
else if (get_day_of_week(month, date, year) == 1)
dayW = "Monday";
else if (get_day_of_week(month, date, year) == 2)
dayW = "Tuesday";
else if (get_day_of_week(month, date, year) == 3)
dayW = "Wednesday";
else if (get_day_of_week(month, date, year) == 4)
dayW = "Thursday";
else if (get_day_of_week(month, date, year) == 5)
dayW = "Friday";
else if (get_day_of_week(month, date, year) == 6)
dayW = "Saturday";
else
dayW = "INVALID";
cout << dayW;
}
}
void print() {
string dayW;
if (get_day_of_week(month, date, year) == 0)
dayW = "Sunday";
else if (get_day_of_week(month, date, year) == 1)
dayW = "Monday";
else if (get_day_of_week(month, date, year) == 2)
dayW = "Tuesday";
else if (get_day_of_week(month, date, year) == 3)
dayW = "Wednesday";
else if (get_day_of_week(month, date, year) == 4)
dayW = "Thursday";
else if (get_day_of_week(month, date, year) == 5)
dayW = "Friday";
else if (get_day_of_week(month, date, year) == 6)
dayW = "Saturday";
else
dayW = "INVALID";
cout << "Today is " << dayW << " " << month <<
" " << date << " " << year << endl; //prints out day and full date
}
void reset(int newDate,int newMonth, int newYear) {
newDate = date;
newMonth = month;
newYear = year;
}
};
int main()
{
int i = 3;
int z = 31;
int f = 2017;
Date today(i,z,f); // 03/31/2017
today.print();
Date firstDay; // will be 01/01/2017
firstDay.print();
Sleep(50000);
return 0;
}
最佳答案
您的作业倒退了。
Date(int fmonth, int fdate, int fyear) {
fmonth = month;
fdate = date;
fyear = year;
}
应该是
Date(int fmonth, int fdate, int fyear) {
month = fmonth;
date = fdate;
year = fyear;
}
关于C++重载构造函数问题，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/43300965/