c++ - 使用两个链表

Question

我需要创建两个单独的链表，然后比较它们。但是，当我尝试为构造函数创建具有相同运算符重载的第二个列表时，出现错误:

“多项式2*类型的值不能用于初始化多项式*类型的实体”

这是我的代码:

标题:

#include <iostream>
#include <string>

using namespace std; 

struct polynomial
{ 
    polynomial();
    polynomial(string newCoefficient, string newPower, polynomial *nextPtr);
    string coefficient;
    string power;
    polynomial *next; 
};

struct polynomial2
{ 
    polynomial2();
    polynomial2(string newCoefficient2, string newPower2, polynomial2 *nextPtr2);
    string coefficient2;
    string power2;
    polynomial *next2; 
};

class linkedList
{
public:
    linkedList();
    void callFunctions();
private:
    polynomial *head;
    polynomial2 *head2;
    void makeList(polynomial *head, polynomial2 *head2);
    void showList(polynomial *head);
    void compareNodes(polynomial *head, polynomial2 *head2);
};

#endif
/* defined(__Assignment3__Polynomial__) */

.CPP代码:

linkedList::linkedList()
{
    head = 0; 
};

polynomial::polynomial()
{
    coefficient = " "; 
    power = " "; 
    next = NULL;
};

polynomial2::polynomial2()
{
    coefficient2 = " "; 
    power2 = " "; 
    next2 = NULL
};

polynomial::polynomial(string newCoefficient, string newPower, polynomial *nextPtr )
    :
coefficient(newCoefficient),
    power(newPower), 
    next(nextPtr) 

{}

polynomial2::polynomial2(string newCoefficient2, string newPower2, polynomial2 *nextPtr2)
    :
coefficient2(newCoefficient2),
    power2(newPower2), 
    next2(nextPtr2)

{}

错误出现在 .cpp 文件的最后一行“next2(nextPtr2)”。 “nextPtr2”带下划线

Answer 1

在您的 polynomial2 定义中，您的意思是:

polynomial2 *next2;

代替

polynomial *next2;