C++陷入死循环

Question

好的伙计们，我是编程新手，需要一些帮助。我有一个程序可以输入一个句子并显示单词和元音的数量。然后，如果用户需要，我想重复该程序，但是当我使用 do-while 循环时，in 陷入无限循环。在我输入“Y”进行重复后，它会循环显示我为上一个句子输入的元音和单词数。

这是我的代码:

#include "stdafx.h"
#include <iostream>
#include <iomanip>
#include <conio.h>

using namespace std;


int _tmain(int argc, _TCHAR* argv[])
{
    char sentence[50];
    int countA=0, countE=0, countI=0, countO=0, countU=0, countSP=0;
    char repeat;

    do {
    cout << "Enter sentence : ";
    cin.get(sentence, 50, '\n'); cin.ignore(10, '\n');


    cout << sentence;
    cout << "\nThird character is : " << sentence[2];
    cout << "\nLast character is : " << sentence[strlen(sentence)-1];
    cout << "\nLength of sentence is : " << strlen(sentence);

    for(int x=0; x < strlen(sentence); x++) {
        char ch = tolower (sentence[x]);
        switch (ch) {
        case 'a':   countA++;break;
        case 'e':   countE++;break;
        case 'i':   countI++;break;
        case 'o':   countO++;break;
        case 'u':   countU++;break;
        case ' ':   countSP++;break;
        }
    }


    cout << "\nNumber of A's : " << countA;
    cout << "\nNumber of E's : " << countE;
    cout << "\nNumber of I's : " << countI;
    cout << "\nNumber of O's : " << countO;
    cout << "\nNumber of U's : " << countU;
    cout << "\nNumber of words : " << countSP+1;

    cout << "\n\nWould you like to enter a new sentence? (Y/N): ";
    cin >> repeat;

    }while (repeat == 'y' || repeat == 'Y');

    _getche();
    return 0;
}

Answer 1

表达式 (repeat == 'y' && repeat == 'Y') 将总是等于 false，因为 repeat 不能等于 'y' 和 'Y'。

你的意思可能是:

(repeat == 'y' || repeat == 'Y');