c++ - 错误 C2679 : binary '=' : no operator found which takes a right-hand operand of type 'School *' (or there is no acceptable conversion)

Question

我正在尝试学习如何使用数组/指针访问构造函数。 我知道如何访问类成员函数，但我一直卡在如何访问构造函数上。

这个程序: 1.询问学校数量。 2.询问学校名称。 3.显示每个学校的名称。

#include<iostream>
#include<string>
using namespace std;

class School
{
public:
    School(string name = "")
    {   schoolname = name;}

    void Display()
    {   cout << "School name is " << schoolname;}

private:
    string schoolname;
};

int main()
{
    string sname;
    int schoolNO;
    School *myschool;
    myschool[10];

    cout << "Enter number of school : ";
    cin >> schoolNO;

    for (int i = 0; i < schoolNO; i++)
    {
        cout << "Enter school name : ";
        cin >> sname;

        myschool[i] = new School(sname);*//The error stated is in this line...*
        myschool[i].Display();
    }
}

Answer 1

问题是 mySchool 是一个对象数组，而不是指针数组，因此您不能使用 new 将指针分配给它的元素。

替换这个:

School *myschool;
myschool[10];

为此:

School* myschool[10];

现在您有了一个指针数组，new 将起作用。