c++ - 比较 C++ 时常量超出范围

Question

我刚刚从我的项目中创建了一个 C++ 问题，我编译了程序并没有给我错误，但给了我一个警告，我无法运行或测试该程序。

#include <iostreamn.h>
#include <conio.h>
#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main()
{
    int grossincome,totaldeduction,tax,output;

    cout<<"Input gross income: "<<endl;
    cin>>grossincome;
    cout<<"Input total deductions: "<<endl;
    cin>>totaldeduction;

    if (grossincome > 100000)
    {
       tax = (grossincome * .20);
       output = (grossincome - totaldeduction - tax);
    }
    else if((grossincome <= 100000) && (grossincome >= 50000))
    {
       tax = (grossincome * .15);
       output = (grossincome - totaldeduction - tax);
    }
    else if(grossincome < 50000)
    {
       tax = (grossincome * .10);
       output = (grossincome - totaldeduction - tax);
    }
    cout<<"Output: "<<output;
    system("pause");
    return 0;
}

我在所有 If 语句 中都收到警告，并在下面说出消息。

  WARNING message: "Warning Q4.CPP 16: Constant out of range in comparison"
                   "Warning Q4.CPP 21: Constant out of range in comparison"
                   "Warning Q4.CPP 21: Constant out of range in comparison"
                   "Warning Q4.CPP 26: Constant out of range in comparison"

Answer 1

Turbo C/C++ 是一个旧的编译器。 int 的范围是从 -32768 到 +32767。
要么你可以切换到更好的标准编译器(如 gcc)，要么使用 long 修饰符。