c++ - 猜数字 - 读取错误时无限循环

Question

所以我正在用 C++ 制作这个猜数字游戏，看起来像这样:

#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;

int main()
{
    srand(time(0));
    int secretNumber = rand() % 100 + 1; //Generate "Random number"
    int nbrOfGuesses = 0;
    int userInput;

    cout<<"\t************************************"<<endl;
    cout<<"\t*                                  *"<<endl;
    cout<<"\t*          Guess the number!       *"<<endl;
    cout<<"\t*                                  *"<<endl;
    cout<<"\t************************************"<<endl;
    cout<<endl;
    cout << "Try to find the secret int number: " << endl;

    //While input is good
    while(cin.good())
    {
        //Do this
        do {
            cin>>userInput;
            nbrOfGuesses++;

            if (userInput>secretNumber)
                cout << "Smaller!\n";

            else if(userInput<secretNumber)
                cout << "Bigger!\n"; // <-- Infinite loop here when you enter something other than an integer

            else //Also using this as a backup of (cin.good())
                cout << "Something went wrong with the read";
                break;

        } while(userInput!=secretNumber);
                cout << "\nCongratulations! You got it in " << nbrOfGuesses << " guesses\n";
    }

    system("pause");
    return 0;
}

*抱歉，如果代码非常优雅

如您所见，代码运行良好，直到您输入一个随机字符，如“&”或“j”或任何其他非整数...然后它在 cout<<"Bigger!"; 处循环。

所以我的问题是:造成这种情况的原因是什么？

Answer 1

检查 this post ，这是关于同样的问题。总结:

cin>>userInput;
if (cin.fail()) {
  cout<<"Invalid Entry, please try again."<<endl;
  cin.clear();
  cin.ignore(numeric_limits<streamsize>::max(), '\n');
}

感谢 ildjarn 指出缺少的忽略语句，我错过了那部分，尽管它在我链接的帖子中明确提到了!!