我有一个 C++ 类模板和另一个继承它的类。正如您将看到的,后者不是类模板。当我尝试通过调用基类(模板)的构造函数来定义派生类的构造函数时,问题就出现了。我已将错误发布在代码下方。
为简单起见,我只添加了声明。如果您觉得代码可以帮助您了解问题所在,我很乐意发布它。
状态2d.h
#ifndef STATE2D_H
#define STATE2D_H
template <typename T>
class State2D
{
public:
State2D(unsigned int _rows, unsigned int _columns);
State2D(unsigned int _rows, unsigned int _columns, const T& val);
State2D(const State2D<T> &st);
~State2D();
T& operator()(unsigned int i, unsigned int j);
const T& operator()(unsigned int i, unsigned int j) const;
unsigned int GetRowCount() const;
unsigned int GetColumnCount() const;
unsigned int GetAvailablePositionsCount() const;
protected:
T** matrix;
unsigned int rows;
unsigned int columns;
unsigned int availablePositions;
};
#endif // STATE2D_H
TicTacToeState.h
#ifndef TICTACTOESTATE_H
#define TICTACTOESTATE_H
#include "state2d.h"
class TicTacToeState : public State2D<char>
{
public:
TicTacToeState();
};
#endif // TICTACTOESTATE_H
井字游戏状态.cpp
#include "tictactoestate.h"
TicTacToeState::TicTacToeState() : State2D(3,3,' ') // ERROR here; see below
{
}
error: class 'TicTacToeState' does not have any field named 'State2D' error: no matching function for call to 'State2D::State2D()' candidates are: State2D::State2D(const State2D&) [with T = char] State2D::State2D(unsigned int, unsigned int, const T&) [with T = char] State2D::State2D(unsigned int, unsigned int) [with T = char]
有什么想法吗?
最佳答案
: State2D<char>(3,3,' ')
也许吧?
关于c++ - 模板继承,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12460960/