给定代码:
int arr[] = {11,22,33,44,55}
for(int i = 0; i <5 ; i++)
cout << *(arr+i) << " ";
*(arr+i)和arr[i]的效果一样吗？
最佳答案
是的。事实上，下标运算符 E1[E2] 被定义为等同于 *((E1)+(E2)):
A postfix expression followed by an expression in square brackets is a postfix expression. One of the expressions shall have the type “pointer to
T” and the other shall have unscoped enumeration or integral type. The result is an lvalue of type “T.” The type “T” shall be a completely-defined object type. The expressionE1[E2]is identical (by definition) to*((E1)+(E2)).
关于C++ 指针运算，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16223375/