在最后一天,我在使用这段代码时遇到了一些问题。这里我想用 .txt 上传几个十六进制值,如果前五个数字的总和等于最后一个数字,代码是正确的。然后,方法 main 必须检查其余方法是否成功。但我不知道该怎么做,所以我需要你的帮助...
#include <iostream>
#include <fstream>
#define FILECODE "file.txt"
#define N_CODE 6
using namespace std;
ifstream file;
void uploadCode(bool& exist, unsigned int longCode, unsigned int code[]);
bool IsValidCode(unsigned int code[]);
void main() {
unsigned int code[N_CODE];
bool exist;
unsigned int longCode=N_CODE;
IsValidCode(code);
if(IsValidCode(code)==true){
uploadCode(exist,longCode,code); //here I have the problem because I don't know how to call the method
cout << "SUCCESS" << endl;
}
else
cout << "FAIL" << endl;
}
void uploadCode(bool& exist, unsigned int longCode, unsigned int code[]) {
int i;
file.open(FILECODE);
if(file){
exist=true;
for(int i=0;i<longCode;i++){
file >> hex >> code[i];
cout << "Number " << i << ": "<< code[i] << endl;
}
cout << "EXIST" << endl;
}
else
cout << "NO EXIST" << endl;
exist=false;
file.close();
}
bool IsValidCode(unsigned int code[]) {
int i;
int sum=0;
for(int i=0; i<N_CODE-1; i++)
sum+=code[i];
cout << "Sum first five numbers: " << sum << endl;
if(sum==code[6])
return true;
else
return false;
return sum;
}
最佳答案
这是一个最小修改的版本,可以满足您的需求。当然,应该对输入处理的返回值进行更好的检查(即 - file >> hex >> code[i];
)以查看这些输入是否真的成功。
bool uploadCode(unsigned int longCode, unsigned int code[])
{
bool ret;
file.open(FILECODE); // TODO: no need for a global here; just use a locally constructed ifstream
if (file.good())
{
ret = true;
for(int i = 0; i < longCode; ++i)
{
file >> hex >> code[i];
cout << "Number " << i << ": "<< code[i] << endl;
}
cout << "EXIST" << endl;
}
else
{
ret = false;
cout << "NO EXIST" << endl;
}
file.close();
return ret;
}
int main()
{
unsigned int code[N_CODE];
if (!uploadCode(N_CODE, code))
{
cout << "File failure!" << endl;
return 1;
}
if (!IsValidCode(code))
{
cout << "Code failure!" << endl;
return 2;
}
cout << "SUCCESS" << endl;
return 0;
}
关于c++ - C++ 中具有十六进制值的数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29173806/