我正在为 STL 容器的反序列化编写模板类。
假设我想序列化一个 set<int>
.我有一个基地 serialisation
类和以下模板:
template<typename T>class serialiser;
template<>class serialiser<int>:public serialisation<int>{
public:
void serialise ( int t );
};
序列化set
,我有:
template<typename T>class Container_serialiser:public serialisation<T>{
public:
void serialise ( T t );
private:
/* Notice that I must declare a serialiser.
*/
serialiser<typename T :: value_type>value_serialiser;
};
template<typename T>void Container_serialiser<T>::serialise ( T t ){
for(typename T :: const_iterator t_iterator = t . begin ( );t_iterator != t . end ( );++ t_iterator){
value_serialiser . serialise ( * t_iterator );
}
}
这仅适用于其元素本身不构成容器的容器。
问题
如果我想序列化一个 map<int,set<int> >
怎么办? ?
因为每个元素的类型都是 pair<int,set<int> >
,我需要以下类(class):
template<>class serialiser<pair<int,set<int> > >:public serialisation<pair<int,set<int> > >{
public:
void serialise ( const pair<int,set<int> >t );
private:
serialiser<int>t_first_serialiser;
/* Notice that I must declare a Container_serialiser.
*/
Container_serialiser<set<int> >t_second_serialiser;
};
然而,Container_serialiser
需要 serialiser<T>
成为一个完整的类型。因此,它不能在上面的类之后定义。同样,上面的类需要 Container_serialiser<T>
是一个完整的类型,不能在它之前定义。
编译器报如下错误:
prog.cpp: In instantiation of 'class Container_serialiser<std::map<int, std::set<int> > >':
prog.cpp:73:44: required from here
prog.cpp:40:39: error: 'Container_serialiser<T>::value_serialiser' has incomplete type
serialiser<typename T :: value_type>value_serialiser;
^
prog.cpp:25:27: note: declaration of 'class serialiser<std::pair<const int, std::set<int> > >'
template<typename T>class serialiser;
问题代码
#include <iostream>
#include <map>
#include <set>
#include <utility>
using std :: cout;
using std :: map;
using std :: set;
using std :: make_pair;
using std :: pair;
template<typename T>class serialisation{
public:
virtual ~serialisation ( );
protected:
virtual void serialise ( const T t ) = 0;
};
template<typename T>serialisation<T> :: ~serialisation ( ){
}
template<typename T>class serialiser;
template<>class serialiser<int>:public serialisation<int>{
public:
void serialise ( const int t );
};
void serialiser<int>:: serialise ( const int t ){
cout << t << '\n';
}
template<typename T>class Container_serialiser:public serialisation<T>{
public:
void serialise ( const T t );
private:
serialiser<typename T :: value_type>value_serialiser;
};
template<typename T>void Container_serialiser<T>:: serialise ( const T t ){
for(typename T :: const_iterator t_iterator = t . begin ( );t_iterator != t . end ( );++ t_iterator){
value_serialiser . serialise ( * t_iterator );
}
}
template<>class serialiser<pair<int,set<int> > >:public serialisation<pair<int,set<int> > >{
public:
void serialise ( const pair<int,set<int> >t );
private:
serialiser<int>t_first_serialiser;
Container_serialiser<set<int> >t_second_serialiser;
};
void serialiser<pair<int,set<int> > >:: serialise ( const pair<int,set<int> >t ){
t_first_serialiser . serialise ( t . first );
t_second_serialiser . serialise ( t . second );
}
int main ( ){
set<int>t;
t . insert ( 2 );
t . insert ( 3 );
Container_serialiser<set<int> >t_serialiser;
t_serialiser . serialise ( t );
map<int,set<int> >u;
u . insert ( make_pair ( 5,t ) );
u . insert ( make_pair ( 7,t ) );
Container_serialiser<map<int,set<int> > >u_serialiser;
u_serialiser . serialise ( u );
}
黑客
我可以通过编写四个模板来完成这项工作:
-
serialiser0<T>
对于所有不是容器且不包含容器的 T -
Container_serialiser0<T>
对于value_type
的所有 T是serialiser0<T>
的参数 -
serialiser1<T>
对于所有不是容器但包含本身不包含容器的元素的容器的 T -
Container_serialiser1<T>
对于value_type
的所有 T是serialiser1<T>
的参数
这种设计是重复的、令人困惑的,并且必须为每个新级别的容器手动扩展。有没有更好的模式?
不幸的是,由于我正在从事的项目,我必须避免外部依赖,例如boost.serialization。甚至以牺牲性能为代价并为 C++98 标准编写代码。
破解代码
#include <iostream>
#include <map>
#include <set>
#include <utility>
using std :: cout;
using std :: map;
using std :: set;
using std :: make_pair;
using std :: pair;
template<typename T>class serialisation{
public:
virtual ~serialisation ( );
protected:
virtual void serialise ( const T t ) = 0;
};
template<typename T>serialisation<T> :: ~serialisation ( ){
}
template<typename T>class serialiser0;
template<>class serialiser0<int>:public serialisation<int>{
public:
void serialise ( const int t );
};
void serialiser0<int>:: serialise ( const int t ){
cout << t << '\n';
}
template<typename T>class Container_serialiser0:public serialisation<T>{
public:
void serialise ( const T t );
private:
serialiser0<typename T :: value_type>value_serialiser;
};
template<typename T>void Container_serialiser0<T>:: serialise ( const T t ){
for(typename T :: const_iterator t_iterator = t . begin ( );t_iterator != t . end ( );++ t_iterator){
value_serialiser . serialise ( * t_iterator );
}
}
template<typename T>class serialiser1;
template<>class serialiser1<pair<const int,set<int> > >:public serialisation<pair<int,set<int> > >{
public:
void serialise ( const pair<int,set<int> >t );
private:
serialiser0<int>t_first_serialiser;
Container_serialiser0<set<int> >t_second_serialiser;
};
void serialiser1<pair<const int,set<int> > >:: serialise ( const pair<int,set<int> >t ){
t_first_serialiser . serialise ( t . first );
t_second_serialiser . serialise ( t . second );
}
/* This is the same as Container_serialiser0!
*/
template<typename T>class Container_serialiser1:public serialisation<T>{
public:
void serialise ( const T t );
private:
serialiser1<typename T :: value_type>value_serialiser;
};
template<typename T>void Container_serialiser1<T>:: serialise ( const T t ){
for(typename T :: const_iterator t_iterator = t . begin ( );t_iterator != t . end ( );++ t_iterator){
value_serialiser . serialise ( * t_iterator );
}
}
int main ( ){
set<int>t;
t . insert ( 2 );
t . insert ( 3 );
Container_serialiser0<set<int> >t_serialiser;
t_serialiser . serialise ( t );
map<int,set<int> >u;
u . insert ( make_pair ( 5,t ) );
u . insert ( make_pair ( 7,t ) );
Container_serialiser1<map<int,set<int> > >u_serialiser;
u_serialiser . serialise ( u );
}
最佳答案
(我必须承认我忘记了这个问题。)
感谢@michael-gopshtein 的评论,我最终偶然发现了 partial template specialization ,很好的解决了这个问题。请注意,我必须同时使用 template <typename SerialisedType> class Serialiser
和 template <typename SerialisedType> inline void serialise(const SerialisedType &x)
.函数本身不能部分特化,但是 Serialiser::serialise
的大部分特化取决于对 ::serialise
的一般调用.
序列化 std::map<int, std::set<int>>
,我会写以下内容:
#include <map>
#include <set>
#include <utility>
// For the sake of having a MWE, I'll just write int-s to stdout.
#include <iostream>
template <typename SerialisedType> class Serialiser;
template <typename SerialisedType>
inline void serialise(const SerialisedType &x) {
Serialiser<SerialisedType>::serialise(x);
}
template <> class Serialiser<int> {
public:
inline static void serialise(const int &x);
};
template <typename Key> class Serialiser<std::set<Key>> {
public:
inline static void serialise(const std::set<Key> &x);
};
template <typename T1, typename T2> class Serialiser<std::pair<T1, T2>> {
public:
inline static void serialise(const std::pair<T1, T2> &x);
};
template <typename Key, typename T>
class Serialiser<std::map<Key, T>> {
public:
inline static void serialise(const std::map<Key, T> &x);
};
void Serialiser<int>::serialise(const int &x) {
std::cout << x << "\n";
}
template <typename Key>
void Serialiser<std::set<Key>>::serialise(const std::set<Key> &x) {
{
const typename std::set<Key>::const_iterator x_cend = x.cend();
for (typename std::set<Key>::const_iterator x_iterator = x.cbegin();
x_iterator != x_cend; ++x_iterator)
::serialise(*x_iterator);
}
}
template <typename T1, typename T2>
void Serialiser<std::pair<T1, T2>>::serialise(const std::pair<T1, T2> &x) {
::serialise(x.first);
::serialise(x.second);
}
template <typename Key, typename T>
void Serialiser<std::map<Key, T>>::serialise(const std::map<Key, T> &x) {
{
const typename std::map<Key, T>::const_iterator x_cend = x.cend();
for (typename std::map<Key, T>::const_iterator x_iterator = x.cbegin();
x_iterator != x_cend; ++x_iterator)
::serialise(*x_iterator);
}
}
int main() {
std::map<int, std::set<int>> u {
{5, {2, 3}},
{7, {2, 3}}
};
serialise(u);
}
输出:
5
2
3
7
2
3
关于c++ - 如何避免序列化器和容器序列化器之间的循环模板依赖?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33326868/