我目前正在开发一个处于早期阶段的虚拟运行时环境程序,由于使用我的 makefile 时出现链接器错误,我无法继续我的工作,如下所示。我收到的错误是:
g++ controller.o processor.o test.o -o final
controller.o: In function `Controller::run()':
controller.cpp:(.text+0x1e0): undefined reference to
Processor::codeParams(char)'
controller.o: In function `Controller::fetch()':
controller.cpp:(.text+0x290): undefined reference to `Controller::pc'
controller.cpp:(.text+0x299): undefined reference to `Controller::pc'
collect2: error: ld returned 1 exit status
makefile:16: recipe for target 'final' failed
make: *** [final] Error 1
我不确定为什么会出现此错误,因为我认为我已经在与 header 对应的源文件中定义了这些内容。下面将给出所有文件,以便编译程序。
测试.cpp:
#include <iostream>
#include <vector>
#include "includes/controller.h"
using namespace std;
int main()
{
vector<char> prog = {0x0};
Controller contr(prog);
cout << "Error Code: " << contr.run() << endl;
return 0;
}
Controller .cpp:
/*
Author(s): James Dolan
File: controller.cpp
Build: 0.0.0
Header: includes/controller.h
DoLR: 21:39 11/1/2017
Todo: n/a
*/
#include "includes/controller.h"
Controller::Controller(vector<char> prog)
{
printf("Program:"); //Display program
for(auto i : program)
{
printf("%02X", i);
}
printf("\n");
Controller::program = program;
}
Controller::~Controller ()
{
}
int Controller::run()
{
bool runFlag = true;
int errorCode = 0;
char curCode;
vector<char> curInstr;
int paramRef;
while(runFlag)
{
curCode = fetch();
printf("curCode:%02X\n", curCode);
curInstr.push_back(curCode);
paramRef = proc.codeParams(curCode);
if (paramRef == 0xffff){runFlag = false; continue;} //Check if shutdown signal was returned, if so shutdown
printf("opcode good\n");
for(int i; i<paramRef; i++){curInstr.push_back(fetch());}
}
return errorCode;
}
char Controller::fetch()
{
return program[pc++]; //Return next instruction then increment the program counter
}
Controller .h:
/*
Author(s): James Dolan
File: controller.h
Source: ../controller.cpp
DoLR: 21:39 11/1/2017
Todo: n/a
*/
#ifndef CONTROLLER_H
#define CONTROLLER_H
#include <iostream>
#include <vector>
#include <cstdlib>
#include "processor.h"
using namespace std;
class Controller{
public:
Controller(vector<char> prog);
~Controller();
int run();
protected:
private:
vector<char> program;
static int pc;
char fetch();
Processor proc();
};
#endif
处理器.cpp:
#include "includes/processor.h"
Processor::Processor()
{
}
Processor::~Processor()
{
}
int codeParams(char code)
{
switch(code)
{
case 0x0: //Halt
return 0;
default:
printf("[ERROR!] Invalid opcode [%02X]", code);
return 0xffff; //Return shutdown signal
}
}
处理器.h:
#ifndef PROCESSOR_H
#define PROCESSOR_H
#include <iostream>
#include <cstdlib>
class Processor{
public:
Processor();
~Processor();
int codeParams(char code);
protected:
private:
};
#endif
如果有任何帮助,我将不胜感激,因为它将帮助我继续我的热情,开发一个完全成熟的开源虚拟运行时环境,如 java vm,感谢您抽出时间。
最佳答案
在 Controller.cpp 中你需要一个 int Controller::pc;
或 int Controller::pc = 0;
在头文件中,您声明了一个存在于某处的名为 pc 的静态整数。它需要实际存在于某处的翻译单元中(在本例中为 Controller.cpp),以便当链接器试图找到它时......它存在。
在 Processor.cpp 中,您的签名应该类似于 int Processor::codeParams(char code)
让编译器知道这是 Processor 的 codeParams 而不是名为 codeParams 的随机函数恰好也采用性格。
关于c++ - G++ - 未定义对已定义成员函数的引用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41618972/