c++ - 将字符串解析为int

Question

我对编码还很陌生，我希望有人能帮助我？我试图读取一行空格分隔的整数并将它们解析为(最终解析为链接列表) vector 。

所以一旦我有了一个整数 vector ，就有了STL vector 的迭代器，但是我如何迭代链接列表中不在STL中的节点？

#include <cstdlib>
#include <iostream>
#include <string>
#include <sstream>
#include <vector>

using namespace std;

int main(int argc, char** argv) {    
    cout << "Enter some integers, space delimited:\n";
    string someString;
    getline(cin, someString);

    istringstream stringStream( someString );
    vector<string> parsedString;
    char splitToken = ' ';

    //read throguh the stream
    while(!stringstream.eof()){
        string subString;
        getline( stringStream, subString, splitToken);
        if(subString != ""){
        parsedString.push_back(subString);
        }
   }

    return EXIT_SUCCESS;
}

Answer 1

stringstream 可以自动处理如下分隔符:

cout << "Enter some integers, space delimited:\n";
string someString;
getline(cin, someString);

istringstream stringStream( someString );
vector<int> integers;
int n;
while (stringStream >> n)
    integers.push_back(n);