第一阶段
示例 1:我有 string text = "01100001"
然后我想写入文件 "a"
示例 2:我有 string text = "0110000101100010"
所以我想写入文件 "ab"
注意:
我解决了阶段 1
并且写入结果为真。
第 2 阶段
例如1:
I want read the file and put it to temp.
So temp = "a" and i convert it to "01100001"
例如2:
I want read the file and put it to temp.
So temp = "ab" and i convert it to "0110000101100010"
问题
在我的代码中我有以下输入
string text ="00000110101011100010001011111110011011110101100101110101101111010111111110101011"
"00111011000011100011100000100010111110111110111001100001110001110000101001111010"
"00000101";
我做了“第 1 阶段”,我在十六进制编辑器中打开文件,文字是真实的。
但是在执行“第 2 阶段”之后 temp != text。为什么?
我的代码
#include <iostream>
#include <sstream>
#include <vector>
#include <fstream>
#include <string>
#include <stdlib.h>
using namespace std;
class bitChar{
public:
unsigned char* c;
int shift_count;
string BITS;
bitChar()
{
shift_count = 0;
c = (unsigned char*)calloc(1, sizeof(char));
}
string readByBits(ifstream& inf)
{
string s ="";
while (inf)
{
string strInput;
getline(inf, strInput );
for (int i =0 ; i < strInput.size() ; i++)
{
s += getBits(strInput[i]);
}
}
return s;
}
void setBITS(string X)
{
BITS = X;
}
int insertBits(ofstream& outf)
{
int total = 0 ;
while(BITS.length())
{
if(BITS[0] == '1')
*c |= 1;
*c <<= 1;
++shift_count;
++total;
BITS.erase(0, 1);
if(shift_count == 7 )
{
if(BITS.size()>0)
{
if(BITS[0] == '1')
*c |= 1;
++total;
BITS.erase(0, 1);
}
writeBits(outf);
shift_count = 0;
free(c);
c = (unsigned char*)calloc(1, sizeof(char));
}
}
if(shift_count > 0)
{
*c <<= (7 - shift_count);
writeBits(outf);
free(c);
c = (unsigned char*)calloc(1, sizeof(char));
}
outf.close();
return total;
}
string getBits(unsigned char X)
{
stringstream itoa;
for(unsigned s = 7; s > 0 ; s--)
{
itoa << ((X >> s) & 1);
}
itoa << (X&1) ;
return itoa.str();
}
void writeBits(ofstream& outf)
{
outf << *c;
}
~bitChar()
{
if(c)
free(c);
}
};
int main()
{
ofstream outf("ssSample.dat",ios::binary);
string text ="00000110101011100010001011111110011011110101100101110101101111010111111110101011"
"00111011000011100011100000100010111110111110111001100001110001110000101001111010"
"00000101";
cout<< text<<endl;
//write to file
bitChar bchar;
bchar.setBITS(text);
bchar.insertBits(outf);
outf.close();
ifstream inf("ssSample.dat" ,ios::binary);
//READ FROM FILE
string temp=bchar.readByBits(inf);
cout << endl;
cout << temp << endl;
return 0;
}
最佳答案
您有一个 LF
换行字符。这是被省略的字符。
0000 1010
这可能无关紧要,但 Windows 需要 CR
和 LF
换行。此代码在 Windows 和 Unix 中的行为可能不同。
一次读取一个字节。
string readByBits(ifstream& inf)
{
string s ="";
char buffer[1];
while (inf.read (buffer, 1))
{
// string strInput;
//getline(inf, strInput );
//for (int i =0 ; i < strInput.size() ; i++)
//{
s += getBits(*buffer);
//}
}
return s;
}
程序输出:
000001101010111000100010111111100110111101011001011101011011110101111111101010110011101100001110001110000010001011111011111011100110000111000111000010100111101000000101
000001101010111000100010111111100110111101011001011101011011110101111111101010110011101100001110001110000010001011111011111011100110000111000111000010100111101000000101
关于c++ - 将字符串写入文件不等于从中读取的字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21000141/