我有一个函数可以遍历一些并行数组并在循环控制变量中打印内容。我有另一个在我的程序中使用的,用于在循环控制变量的值处打印与 ID
关联的名称。这是两个函数
void PrintName(int ID)
{
switch (ID)
{
case 0: cout << "computer(s)";
break;
case 1: cout << "pencil(s)";
break;
case 2: cout << "pen(s)";
break;
case 3: cout << "book(s)";
break;
case 4: cout << "beer(s)";
break;
case 5: cout << "ruler(s)";
break;
case 6: cout << "stereo(s)";
break;
case 7: cout << "refrigerator(s)";
break;
case 8: cout << "desk(s)";
break;
case 9: cout << "backpack(s)";
break;
}
}
void PrintSummary(InvIDList invIDs, ItemQuantity itemQuant, int totalWeight, int totalPurch, int budget)
{
cout << "ID NAME QUANTITY" <<endl;
cout << "--------------------------" <<endl;
for(int i = 0; i < 10; i++){
cout << invIDs[i];
PrintName(i);
cout << itemQuant[i] <<endl;
}
cout << "\n\nTotal Amount Spent: $" << totalPurch <<endl;
cout << "Amount of Budget Remaining: $" << budget <<endl;
cout << "Total Weight of Items Purchased: " << totalWeight <<endl;
}
我希望输出在 ID
、NAME
和 QUANTITY
下很好地对齐,ID
在最左边, QUANTITY
在最右边,NAME
居中。不幸的是,经过数小时的修改代码,我无法弄清楚如何实现这一点,主要是让 QUANTITY
一直向右对齐。
最佳答案
您不想使用 PrintName 函数,而是希望返回一个字符串对象以与 std::cout 一起使用。为了正确对齐列,您可能需要查看 <iomanip>
header ,尤其是 std::setw(n) 操纵器。
这是一个示例,请注意,当我将列宽设置为 16 个字符时,您应该做的是计算每个类别的最大字符数并相应地更改宽度。这样做的好处是您可以为每列指定不同的宽度。
string ReturnName(int ID)
{
switch (ID)
{
case 0: return "computer(s)";
break;
case 1: return "pencil(s)";
break;
case 2: return "pen(s)";
break;
case 3: return "book(s)";
break;
case 4: return "beer(s)";
break;
case 5: return "ruler(s)";
break;
case 6: return "stereo(s)";
break;
case 7: return "refrigerator(s)";
break;
case 8: return "desk(s)";
break;
case 9: return "backpack(s)";
break;
}
}
void PrintSummary(InvIDList invIDs, ItemQuantity itemQuant, int totalWeight, int totalPurch, int budget)
{
cout << left << setw(16) << "ID";
cout << left << setw(16) << "NAME";
cout << left << setw(16) << "QUANTITY" << endl;
cout << "--------------------------------------" << endl;
for(int i = 0; i < 10; i++){
cout << left << setw(16) << invIDs[i];
cout << left << setw(16) << ReturnName(i);
cout << left << setw(16) << itemQuant[i] << endl;
}
cout << "\n\nTotal Amount Spent: $" << totalPurch <<endl;
cout << "Amount of Budget Remaining: $" << budget <<endl;
cout << "Total Weight of Items Purchased: " << totalWeight <<endl;
}
关于C++ - 无法对齐输出,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22945365/