我有一个使用 BeautifulSoup 的输出。
我需要将 'type' 'bs4.element.Tag' 的输出转换为列表，并将该列表导出到名为 COLUMN_A 的 DataFrame 列中
我希望我的输出在第 14 个元素处停止(最后三个
h2没有用)
我的代码:
import requests
from bs4 import BeautifulSoup
url = 'https://www.planetware.com/tourist-attractions-/oslo-n-osl-oslo.htm'
url_get = requests.get(url)
soup = BeautifulSoup(url_get.content, 'html.parser')
attraction_place=soup.find_all('h2', class_="sitename")
for attraction in attraction_place:
print(attraction.text)
type(attraction)
输出:
1 Vigeland Sculpture Park
2 Akershus Fortress
3 Viking Ship Museum
4 The National Museum
5 Munch Museum
6 Royal Palace
7 The Museum of Cultural History
8 Fram Museum
9 Holmenkollen Ski Jump and Museum
10 Oslo Cathedral
11 City Hall (Rådhuset)
12 Aker Brygge
13 Natural History Museum & Botanical Gardens
14 Oslo Opera House and Annual Music Festivals
Where to Stay in Oslo for Sightseeing
Tips and Tours: How to Make the Most of Your Visit to Oslo
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我希望这样的列表:
attraction=[Vigeland Sculpture Park, Akershus Fortress, ......]
非常感谢您。
最佳答案
一个不错的简单方法是采用照片的 alt 属性。这将获得干净的文本输出，并且只有 14 个，无需任何切片/索引。
from bs4 import BeautifulSoup
import requests
r = requests.get('https://www.planetware.com/tourist-attractions-/oslo-n-osl-oslo.htm')
soup = bs(r.content, 'lxml')
attractions = [item['alt'] for item in soup.select('.photo [alt]')]
print(attractions)
关于python - BeautifulSoup 元素输出到列表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/56468212/