python - 将字符串数组中的元素输出到句子

Question

当打印列表 A 中的内容时，代码应输出列表 B 中的字符串元素。

假设我们有

text = ""
letters = ["a", "b", "c"]
names = ["Abby", "Bob", "Carl"]

如何遍历列表以便当文本更新为

text = "a"
output: Abby

text = "ab"
output: "AbbyBob

text = "cab"
output: "CarlAbbyBob"

我曾尝试在 foor 循环中考虑 if 语句，但无法真正弄明白。对于这篇文章，我已将问题简化为三个元素，但该列表有 30 个元素，因此 for 循环是个好主意。

我的尝试

text = ""

for i in text:
    if i == letters[letters ==i]:
        text = text + names[i]

Answer 1

您可以使用字典将字母映射到名称

letter_to_name = dict()

for idx, val in enumerate(letters):
    letter_to_name[val] = names[idx]

#Creates are mapping of letters to name

#whatever is the input text, just iterate over it and select the val for that key

output = ""
for l in text:
    if l not in letter_to_name:
        #Handle this case or continue
    else:
        output += letter_to_name[l]