Python:KeyError/IOError 与 urllib.urlopen

Question

我正在尝试将一些文本传递给此 readability API像这样:

text = 'this reminds me of the Dutch 2001a caravan full of smoky people Auld Lang Syne'
# construct Readability Metrics API url
request_url = 'http://ipeirotis.appspot.com/readability/GetReadabilityScores?format=json&text=%s' % text
request_url = urllib.quote_plus(request_url.encode('utf-8'))
# make request
j = json.load(urllib.urlopen(request_url))

虽然我在最后一行得到了这个错误:

[Errno 2] No such file or directory: 'http://ipeirotis.appspot.com/readability/GetReadabilityScores?format=json&text=this+reminds+me+of+the+Dutch+2001a+caravan+full+of+smoky+people+Auld+Lang+Syne'

但是，错误中的 URL 是有效的，并且在您访问它时会返回响应。如何对 URL 进行编码以便我可以使用 urlopen？非常感谢。

Answer 1

您引用的是完整的 url，包括 http://等等。如果你尝试打印 request_url 的实际值，你会得到

>>> print request_url
http%3A%2F%2Fipeirotis.appspot.com%2Freadability%2FGetReadabilityScores%3Fformat
%3Djson%26text%3Dthis+reminds+me+of+the+Dutch+2001a+caravan+full+of+smoky+people
+Auld+Lang+Syne

这不是你想要的。您只想引用您想要作为网站的单个参数的部分。我尝试了以下方法，它似乎有效:

text = 'this reminds me of the Dutch 2001a caravan full of smoky people Auld Lang Syne'
# construct Readability Metrics API url
request_url = 'http://ipeirotis.appspot.com/readability/GetReadabilityScores?format=json&text=%s' % urllib.quote_plus(text.encode('utf-8'))
# make request
j = json.load(urllib.urlopen(request_url))