python - 计算字符串中最小长度的唯一单词

Question

我必须编写一个函数，它接受两个变量，即一个句子和一个数字。该函数应返回字符串中等于或大于该数字的唯一单词的数量。示例结果应该是:

>>> unique_func("The sky is blue and the ocean is also blue.",3)
    6

我能想到的解决办法就是

def unique_func(sentence,number):
    sentence_split = sentence.lower().split()
    for w in sentence_split:
        if len(w) >= number:

现在我不知道如何继续我的解决方案。谁能帮帮我？

Answer 1

试试这个:

from string import punctuation

def unique_func(sentence, number):
    cnt = 0
    sentence = sentence.translate(None, punctuation).lower()
    for w in set(sentence.split()):
        if len(w) >= number:
            cnt += 1
    return cnt 

或者:

def unique_func(sentence, number):
    sentence = sentence.translate(None, punctuation).lower()
    return len([w for w in set(sentence.split()) if len(w) >= number])