我正在尝试使用 python 从结果文本文件导入数字列表。问题是列表的位置根据所需数据的大小而变化。我感兴趣的结果文件部分如下所示......
Tip Rotation (degrees)
Node , UR[x] , UR[y] , UR[z]
101 , 0.7978 , 0.7955 , -2.6071
102 , -0.7978 , -0.7955 , -2.6071
1303 , 0.7963 , 0.7693 , -2.6053
1304 , 0.7944 , 0.7150 , -2.5948
1305 , 0.7797 , 0.6616 , -2.5697
1306 , 0.7427 , 0.6074 , -2.5279
1307 , 0.6893 , 0.5509 , -2.4701
1308 , 0.6214 , 0.4914 , -2.3998
1309 , 0.5421 , 0.4272 , -2.3227
1310 , 0.4538 , 0.3585 , -2.2451
1311 , 0.3589 , 0.2848 , -2.1736
1312 , 0.2594 , 0.2070 , -2.1141
1313 , 0.1568 , 0.1256 , -2.0715
所以基本上我想在 UR[z] 列中列出值，但是这个 block 的位置根据节点的数量等而有所不同。所以我想说搜索 UR[z]然后返回其列中的值。我也想在不指定节点数的情况下执行此操作，但如果它大大简化了它也可以执行此操作。
任何帮助将不胜感激!干杯!
作为进一步说明，结果文件的其余部分如下!
SUMMARY OF RESULTS
Max tip rotation =,-2.6071,degrees
Min tip rotation =,-2.0493,degrees
Mean tip rotation =,-2.3655,degrees
Max tip displacement =,2.4013,mm
Min tip displacement =,1.0670,mm
Mean tip displacement = ,1.6051,mm
Max Tsai-Wu FC =,0.3904
Max Tsai-Hill FC =,0.3909
PLATE MODEL DATA
Length =,1000.00,mm
Width =,500.00,mm
Pretwist =, 65.00,degrees
Number of mesh elements =, 1250
Number of nodes =, 1326
VAT FIBRE PATH DEFINITION
Fibre path formula =
2
-6.096e-17 x + 1.421e-15 x - 90
Number of partitions = , 50
Partition No , Ply Angle (degrees)
1 ,-90.00
25 ,-90.00
50 ,-90.00
VAT Ply Orientations in each region
Region , Angle (degrees)
1 ,-90.0
2 ,-90.0
3 ,-90.0
4 ,-90.0
5 ,-90.0
6 ,-90.0
7 ,-90.0
8 ,-90.0
9 ,-90.0
10 ,-90.0
11 ,-90.0
12 ,-90.0
13 ,-90.0
14 ,-90.0
15 ,-90.0
16 ,-90.0
17 ,-90.0
18 ,-90.0
19 ,-90.0
20 ,-90.0
21 ,-90.0
22 ,-90.0
23 ,-90.0
24 ,-90.0
25 ,-90.0
26 ,-90.0
27 ,-90.0
28 ,-90.0
29 ,-90.0
30 ,-90.0
31 ,-90.0
32 ,-90.0
33 ,-90.0
34 ,-90.0
35 ,-90.0
36 ,-90.0
37 ,-90.0
38 ,-90.0
39 ,-90.0
40 ,-90.0
41 ,-90.0
42 ,-90.0
43 ,-90.0
44 ,-90.0
45 ,-90.0
46 ,-90.0
47 ,-90.0
48 ,-90.0
49 ,-90.0
50 ,-90.0
ADDITIONAL DATA
Tip Rotation (degrees)
Node , UR[x] , UR[y] , UR[z]
101 , 0.7978 , 0.7955 , -2.6071
102 , -0.7978 , -0.7955 , -2.6071
1303 , 0.7963 , 0.7693 , -2.6053
1304 , 0.7944 , 0.7150 , -2.5948
1305 , 0.7797 , 0.6616 , -2.5697
1306 , 0.7427 , 0.6074 , -2.5279
1307 , 0.6893 , 0.5509 , -2.4701
1308 , 0.6214 , 0.4914 , -2.3998
1309 , 0.5421 , 0.4272 , -2.3227
1310 , 0.4538 , 0.3585 , -2.2451
1311 , 0.3589 , 0.2848 , -2.1736
1312 , 0.2594 , 0.2070 , -2.1141
1313 , 0.1568 , 0.1256 , -2.0715
1314 , 0.0525 , 0.0421 , -2.0493
1315 , -0.0525 , -0.0421 , -2.0493
1316 , -0.1568 , -0.1256 , -2.0715
1317 , -0.2594 , -0.2070 , -2.1141
1318 , -0.3589 , -0.2848 , -2.1736
1319 , -0.4538 , -0.3585 , -2.2451
1320 , -0.5421 , -0.4272 , -2.3227
1321 , -0.6214 , -0.4914 , -2.3998
1322 , -0.6893 , -0.5509 , -2.4701
1323 , -0.7427 , -0.6074 , -2.5279
1324 , -0.7797 , -0.6616 , -2.5697
1325 , -0.7944 , -0.7150 , -2.5948
1326 , -0.7963 , -0.7693 , -2.6053
Tip Displacement (mm)
Node , U[x] , U[y] , U[z]
101 , 9.2757 , -4.6016 , 2.4013
102 , -9.2757 , 4.6016 , 2.4013
1303 , 8.4491 , -4.2173 , 2.2646
1304 , 7.6214 , -3.8331 , 2.1175
1305 , 6.8005 , -3.4481 , 1.9597
1306 , 5.9917 , -3.0625 , 1.8024
1307 , 5.2006 , -2.6792 , 1.6515
1308 , 4.4320 , -2.3003 , 1.5123
1309 , 3.6888 , -1.9278 , 1.3887
1310 , 2.9721 , -1.5627 , 1.2830
1311 , 2.2807 , -1.2054 , 1.1973
1312 , 1.6116 , -0.8552 , 1.1323
1313 , 0.9596 , -0.5107 , 1.0888
1314 , 0.3186 , -0.1698 , 1.0670
1315 , -0.3186 , 0.1698 , 1.0670
1316 , -0.9596 , 0.5107 , 1.0888
1317 , -1.6116 , 0.8552 , 1.1323
1318 , -2.2807 , 1.2054 , 1.1973
1319 , -2.9721 , 1.5627 , 1.2830
1320 , -3.6888 , 1.9278 , 1.3887
1321 , -4.4320 , 2.3003 , 1.5123
1322 , -5.2006 , 2.6792 , 1.6515
1323 , -5.9917 , 3.0625 , 1.8024
1324 , -6.8005 , 3.4481 , 1.9597
1325 , -7.6214 , 3.8331 , 2.1175
1326 , -8.4491 , 4.2173 , 2.2646
END OF RESULTS
我只想看尖端旋转数据部分!
最佳答案
不使用任何模块:
with open('filename') as f:
next(f) #skip first line
nodes = map(str.strip, next(f).split(','))
#find the index of `'UR[z]'` in `nodes` list
column = nodes.index('UR[z]')
#iterate over each line one by one
for line in f:
line = map(str.strip, line.split(','))
#return the desired column
print line[column]
输出:
-2.6071
-2.6071
-2.6053
-2.5948
-2.5697
-2.5279
-2.4701
-2.3998
-2.3227
-2.2451
-2.1736
-2.1141
-2.0715
更新:
with open('filename') as f:
column = None
for line in f:
if 'UR[z]' in line:
line = map(str.strip, line.split(','))
column = line.index('UR[z]')
break
if column is not None:
for line in f:
if not line.strip():
break
print map(str.strip, line.split(','))[column]
输出:
-2.6071
-2.6071
-2.6053
-2.5948
-2.5697
-2.5279
-2.4701
-2.3998
...
-2.5948
-2.6053
关于python - 如何从不同位置的文本文件返回数字列表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/18784518/