Python 在用户生成的整数列表、While 循环和 Try-Except 中防止重复

Question

我希望用户在集合 [1, 100] 中输入 10 个唯一的整数。到目前为止，这是我的代码:

user_list = []
print "\nChoose any 10 discrete integers in the set [1, 100]. Do not choose duplicates."

i = 1

while i < 11:
    try:
        number_choice = int(raw_input("\nNumber %d?\n> " % i))

        if (0 <= number_choice <= 100) and isinstance(number_choice, int):
            i += 1
            user_list.append(number_choice)
            print "Your list so far: %r" % user_list
        elif (number_choice < 0) or (number_choice > 100):
            print "'I said to keep it in the set [1, 100].'"
            pass
        else:
            pass

    except ValueError:
        print "'That isn't a discrete integer, is it?'"

print sorted(user_list)

为了防止重复，我想将第一个 if 改为:

if (0 <= number_choice <= 100) and (isinstance(number_choice, int)) and (number_choice not in user_list):

这会起作用，除了它只会重复 "Number %d?"% i 如果用户输入重复则再次提示。我如何修改此代码，使其首先显示提示符 'I said no duplicates.' 然后恢复循环？

Answer 1

在 i += 1 行之前:

if number_choice in user_list:
    print 'No duplicates!'
    continue