python - 对不一致数量的元素列表的最后一个元素进行排序

Question

简介

跟进 this question .

目的:对元素个数不一致列表的最后一个元素进行排序

方法

代码

import os

cwd = os.getcwd()

for fn in os.listdir(cwd):
    print(fn)

    with open(fn, "r+") as f, open(cwd + "\\all.txt", "r+") as f2:
        lines = sorted(f, key=lambda text: text.split('-', 1)[::-1])
        print(lines)

        my_new_list = [fn + " - " + x for x in lines]
        print (my_new_list)

        f2.write("\n".join(my_new_list))

样本

aa - http://cc
bb - http://bb
cc - http://aa
aa - aa - http://cc
bb - bb - http://bb
cc - cc - http://aa
aa - aa - aa - http://cc
bb - bb - bb - http://bb
cc - cc - cc - http://aa

输出

列表未按最后一个元素排序。看来排序发生在第二个元素上。

当前

sample.txt - aa - aa - aa - http://cc

sample.txt - aa - aa - http://cc

sample.txt - bb - bb - bb - http://bb

sample.txt - bb - bb - http://bb

sample.txt - cc - cc - cc - http://aa
sample.txt - cc - cc - http://aa

sample.txt - cc - http://aa

sample.txt - bb - http://bb

sample.txt - aa - http://cc

预期

sample.txt - cc - http://aa
sample.txt - cc - cc - http://aa
sample.txt - cc - cc - cc - http://aa

sample.txt - bb - http://bb
sample.txt - bb - bb - http://bb
sample.txt - bb - bb - bb - http://bb

sample.txt - aa - http://cc
sample.txt - aa - aa - http://cc
sample.txt - aa - aa - aa - http://cc

Answer 1

你的问题是 text.split('-', 1) 它只分割字符串一次(在 first '-' ).

你实际上想在 last '-' 中拆分，所以你想要 text.rsplit('-', 1)

*注意，rsplit，而不是split :-)