Python如何根据列表中的项目从字符串中剥离字符串

Question

我有一个如下所示的列表:

exclude = ["please", "hi", "team"]

我有一个字符串如下:

text = "Hi team, please help me out."

我希望我的字符串看起来像:

text = ", help me out."

有效地去除列表中可能出现的任何单词 exclude

我尝试了以下:

if any(e in text.lower()) for e in exclude:
         print text.lower().strip(e)

但上面的 if 语句返回一个 bool 值，因此我得到以下错误:

NameError: name 'e' is not defined

我如何完成这项工作？

Answer 1

是这样的吗？

>>> from string import punctuation
>>> ' '.join(x for x in (word.strip(punctuation) for word in text.split())
                                                   if x.lower() not in exclude)
'help me out

如果您想保留 exclude 中不存在的单词的尾随/前导标点符号:

>>> ' '.join(word for word in text.split()
                             if word.strip(punctuation).lower() not in exclude)
'help me out.'

第一个相当于:

>>> out = []
>>> for word in text.split():
        word = word.strip(punctuation)
        if word.lower() not in exclude:
            out.append(word)
>>> ' '.join(out)
'help me out'