python - 所有行都期望第 0 行

Question

from bs4 import BeautifulSoup
import urllib2
from lxml.html import fromstring
import re
import csv
import pandas as pd

wiki = "http://en.wikipedia.org/wiki/List_of_Test_cricket_records"
header = {'User-Agent': 'Mozilla/5.0'} #Needed to prevent 403 error on Wikipedia
req = urllib2.Request(wiki,headers=header)
page = urllib2.urlopen(req)
soup = BeautifulSoup(page)

try:
    table = soup.find_all('table')[1]
except AttributeError as e:
    print 'No tables found, exiting'

#gets all the tr tags

try:
    rows = table.find_all('tr')
except AttributeError as e:
    print 'No table rows found, exiting'

#gets only the 0th row        

try:
    first = table.find_all('tr')[0]
except AttributeError as e:
    print 'No table row found, exiting'

#how to get all rows expect the 0th one??
try:
    allRows = table.find_all('tr')
except AttributeError as e:
    print 'No table row found, exiting'
print allRows

---

我正在寻找一种方法来获取除第 0 行以外的所有行？ 我知道如何获得第 0 行或任何特定行。但我希望每个“tr”标签/行都期望第 0 行。

任何建议

Answer 1

find_all()返回一个 ResultSet 实例，它是一个列表的子类，您可以 slice :

table.find_all('tr')[1:]