python - 如何打印出具有特定质量的列表？

Question

假设我们有 4 个列表:

["LA","California"]
["NV","Nevada"]
["NY","New York"]
["SF","California"]

我如何编写只打印出第一个和第四个列表的代码，因为它们都将 "California" 作为第二个元素？

Answer 1

假设您有一个列表列表:

list_of_lists = [["LA","California"],
                 ["NV","Nevada"],
                 ["NY","New York"],
                 ["SF","California"]]

然后，您可以只打印出最后位置有 "California" 的列表:

for L in list_of_lists:
    if L[-1] == "California":
        print(L)