python - 带有 plotly 的基本条形图

Question

我试着用这段代码做一个条形图

import plotly.plotly as py
import plotly.graph_objs as go

data = [go.Bar(
            x=['giraffes', 'orangutans', 'monkeys'],
            y=[20, 14, 23]
    )]

py.iplot(data, filename='basic-bar')

但是我得到了这个错误:

PlotlyLocalCredentialsError               Traceback (most recent call last)
<ipython-input-42-9eae40f28f37> in <module>()
      3             y=[20, 14, 23]
      4     )]
----> 5 py.iplot(data, filename='basic-bar')

C:\Users\Demonstrator\Anaconda3\lib\site-packages\plotly\plotly\plotly.py

in iplot(figure_or_data, **plot_options) 149 if 'auto_open' not in plot_options: 150 plot_options['auto_open'] = False --> 151 url = plot(figure_or_data, **plot_options) 152 153 if isinstance(figure_or_data, dict):

C:\Users\Demonstrator\Anaconda3\lib\site-packages\plotly\plotly\plotly.py

in plot(figure_or_data, validate, **plot_options) 239 240 plot_options = _plot_option_logic(plot_options) --> 241 res = _send_to_plotly(figure, **plot_options) 242 if res['error'] == '': 243 if plot_options['auto_open']:

C:\Users\Demonstrator\Anaconda3\lib\site-packages\plotly\plotly\plotly.py

in _send_to_plotly(figure, **plot_options) 1401 cls=utils.PlotlyJSONEncoder) 1402 credentials = get_credentials() -> 1403 validate_credentials(credentials) 1404 username = credentials['username'] 1405 api_key = credentials['api_key']

C:\Users\Demonstrator\Anaconda3\lib\site-packages\plotly\plotly\plotly.py

in validate_credentials(credentials) 1350 api_key = credentials.get('api_key') 1351 if not username or not api_key: -> 1352 raise exceptions.PlotlyLocalCredentialsError() 1353 1354

PlotlyLocalCredentialsError: 
Couldn't find a 'username', 'api-key' pair for you on your local machine. To sign in temporarily (until you stop running Python), run:
>>> import plotly.plotly as py
>>> py.sign_in('username', 'api_key')

Even better, save your credentials permanently using the 'tools' module:
>>> import plotly.tools as tls
>>> tls.set_credentials_file(username='username', api_key='api-key')

For more help, see https://plot.ly/python.

有什么想法可以帮助我吗？

谢谢

Answer 1

需要注意错误中的traceback。在这种情况下，它比平时更有帮助。解决方案在这里给你:

PlotlyLocalCredentialsError: 
Couldn't find a 'username', 'api-key' pair for you on your local machine. To sign in temporarily (until you stop running Python), run:
>>> import plotly.plotly as py
>>> py.sign_in('username', 'api_key')

Even better, save your credentials permanently using the 'tools' module:
>>> import plotly.tools as tls
>>> tls.set_credentials_file(username='username', api_key='api-key')

For more help, see https://plot.ly/python. 

因此，在您尝试制作阴谋之前，请输入您在注册网站时使用的凭据。您可能需要在 Web 浏览器中登录并请求生成 API key ，它与您的密码不同。