我有一个包含很多行的数组 test，每行有 3 个数字。我需要为所有 3 个数字均为正数的每一行获取 True，否则为 False。目前我在用
check = np.all((test[:] > 0), axis=1)
测试 看起来像这样
[[ 0.76717743 -0.14548865 0.10444938]
[-0.349094 0.86043484 -0.03470421]
[ 0.61281474 -0.5589774 -0.46888367]
[ 0.106147 -0.15964074 -0.72297835]
[-0.47496423 0.53561226 -0.56997515]
[ 0.11404722 -0.19772103 -0.70308939]
[ 0.05176676 0.68243443 0.10374478]
[ 0.41054414 -0.37773413 -0.65230608]
[-0.51045939 0.81814742 -0.34113701]
[-0.30434684 0.229953 -0.6717718 ]
[ 0.12726272 -0.2157578 -0.6968093 ]
[-0.56914774 0.80530545 -0.27157462]
[-0.10736854 0.76317726 0.08648359]
[-0.30585015 0.85400552 -0.02213381]
[ 0.81378956 -0.20719654 0.04194195]
[-0.57842424 0.70255033 -0.39798076]
[ 0.56074816 -0.54319019 -0.49967448]
[ 0.72422859 -0.58427248 -0.37145212]
[ 0.86456736 -0.45311164 -0.08229539]
[ 0.86428591 -0.43964496 -0.0693436 ]
[ 0.47937801 -0.51390972 -0.53733707]
[ 0.85551894 -0.39396805 -0.01711862]
[ 0.4737934 -0.54178454 -0.50940207]
[ 0.15694062 -0.34735834 -0.61456285]]
我想加快速度。我能做什么？
最佳答案
使用numexpr:
import numexpr as ne
t0, t1, t2 = test[:,0], test[:,1], test[:,2]
check = ne.evaluate('(t0 > 0) & (t1 > 0) & (t2 > 0)')
关于python:进行大规模检查的有效方法，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/42234672/