python - 如何为嵌套列表中的每一行运行一个函数？

Question

我是 Python 新手，正在尝试编写代码来检查嵌套列表是否具有一组有效的数字。每一行和每一列都必须有效。我编写了一个名为 check_sequence 的函数来验证列表是否具有一组有效的数字。我如何从另一个函数调用该函数来检查该行是否有效？因此，例如，对于 check_rows，我需要这样的东西:

check_sequence(list):
  checks if list is valid

check_rows(list):
  For each of the rows in the nested list call check_sequence

这是我的 check_sequence 代码:

def check_sequence(mylist):
    pos = 0
    sequence_counter = 1
    while pos < len(mylist):
        print "The pos is: " + " " + str(pos)
        print "The sequence_counter is:" + " " + str(sequence_counter)
        for number in mylist:
            print "The number is:" + " " + str(number)
            if number == sequence_counter:
                sequence_counter = sequence_counter + 1
                pos = pos + 1
                break
            else:
                # if list is at the last position on the last item
                if sequence_counter not in mylist:
                    print "The pos is:" + " " + str(pos) + " and the last position is:"  + " "  + str(mylist[len(mylist) - 1])
                    print "False"
                    return False
    print "True"
    return True

所以我会像下面这样调用主要方法:

check_square([[1, 2, 3],
           [2, 3, 1],
           [3, 1, 2]])

def check_square(list):
   if check_rows() and check_columns() == True:
       return True
   else:
       return False

Answer 1

这是一个适用于任意二维列表的解决方案。

l = [[1,2,3],[1,2],[1,4,5,6,7]]
try:
    if len([1 for x in reduce(lambda x, y :x + y, l) if type(x) != type(0)]) > 0:
        raise Exception

catch Exception:
   pass # error, do something 

直觉是将列表展平，然后依次检查其类型是否为 int。