Python - 字典中各个键的每个值的平均值

Question

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Answer 1

只是做:

#loop through the dictionary
for key,value in test_dict.items(): 

   #use reduce to calculate the avg
   print(key, reduce(lambda x, y: x + y, test_dict[key]) / len(test_dict[key]))

这将打印:

NJ 66.0
NY 33.8
CT 220.08

编辑:根据 OP 要求的变化:

l = list(iter(test_dict.values()))                      #convert values to list
print(l)
#[[20, 50, 70, 90, 100], [10, 3, 0, 99, 57], [90, 1000, 2, 3.4, 5]]
d={}                                                                  #final ditionary
for i in range(len(l[0])): 
   row_list = [row[i] for row in l]                     #get values column-wise
   d['location'+str(i+1)] = sum(row_list)/len(row_list)               #calculate avg

print(d)
#{'location1': 40.0, 'location2': 351.0, 'location3': 24.0, 'location4': 64.13333333333334, 'location5': 54.0}

注意:您为 loaction4 提出的平均值是错误的。