python - 如何更新 python 列表中的值？

Question

我有一个看起来像这样的元组列表:

[(5, 0, 1, 8), (5, 0, 1, 14, 15), (5, 0, 1, 14, 16)]

我还有一本字典，格式如下:

{0: [], 1: [], 2: [], 3: [], 4: [], 5: ['CVE-2016-3379'], 7: ['CVE-2016-3646'], 8: [], 9: ['CVE-2015-1769'], 10: ['CVE-2016-3364', 'CVE-2016-7193', 'CVE-2016-3363'], 14: [], 15: ['CVE-2015-1769'], 16: ['CVE-2016-3363', 'CVE-2016-7193', 'CVE-2016-3364'], 17: [], 18: [], 19: [], 20: [], 21: ['CVE-2015-1769'], 22: ['CVE-2016-3363', 'CVE-2016-7193', 'CVE-2016-3364'], 26: [], 27: [], 28: [], 29: [], 30: [], 32: []}

如何使用字典中的值更新第一个列表中的值？

例如，我希望 5 成为 5: ['CVE-2016-3379']，0 成为 0 : [] 等

Answer 1

你可以用这个 list comprehension 做到这一点:

res = [tuple('{}: {}'.format(i, my_dict[i]) for i in t) for t in my_list]

输出示例:

>>> my_list = [(5, 0, 1, 8)]
>>> my_dict = {0: [], 1: [], 5: ['CVE-2016-3379'], 8: []}
>>> res = [tuple('{}: {}'.format(i, my_dict[i]) for i in t) for t in my_list]
>>> res
[("5: ['CVE-2016-3379']", '0: []', '1: []', '8: []')]