python - 如何在Python中增量打印字符串中的字符

Question

s = 'fo12--'
for a in s:
    a+= 1
    print(s[a])

我希望

f  o  1  2 - -

但出现一些类型错误。我可以猜测'a'在这里是一个int，但是我该如何改进这段代码

Answer 1

它是(对于Python 3):

s = 'fo12--'
for a in s:
    print(a, end = " ")

对于Python 2:

s = 'fo12--'
for a in s:
    print a,

参见a demo on ideone.com 。

---

您不需要摆弄其他编程语言中已知的 a[index] 语法。如果您也想拥有索引，enumerate() 是您的 friend :

s = 'fo12--'
for idx, char in enumerate(s):
    # char holds the actual character
    # idx is an increasing integer, starting from zero