python - sqlite3 不按计数分组

Question

我试图返回列中唯一值的数量，但它没有按预期工作。例如:

select columnName, count(columnName) as CountOf from tableName group by columnName
result = c.fetchone()
print result

....将返回:

(627, 1)
(399, 1)
(1714, 1)
(1714, 1)
(88, 1)
(88, 1)

我也试过:

SELECT COUNT(DISTINCT column_name) AS some_alias FROM table_name
result = c.fetchone()
print result

...返回:

(1,)
(1,)
(1,)
(1,)
(1,)
(1,)

期望的输出(关于第一条语句)类似于:

(627, 1)
(399, 1)
(1714, 2)
(88, 2)

我使用的代码是:

def alertsSQL(inputA):

    conn = sqlite3.connect(':memory:')
    c = conn.cursor()
    allT = "SELECT * FROM Alerts"

    c.execute("CREATE TABLE Alerts (SID INT, Signature TEXT)")
    c.execute("INSERT INTO Alerts (SID, Signature) VALUES (?,?)", (inputA))
    conn.commit()

    c.execute('SELECT SID, count(*) as CountOf from Alerts group by SID')
    result=c.fetchall()

    print result

输入“inputA”的列表具有以下性质:

[1714, 'NETBIOS SMB-DS Session Setup']

注意在上面的代码中，为了清楚起见，我只是减少了列数。数据已正确插入，我通过以下方式验证:

for row in c.execute(allT):
        print row

生成表中的每一行，例如一排是:

(1714, u'NETBIOS SMB-DS Session Setup')

Answer 1

您正在使用:

select columnName, count(columnName) as CountOf from tableName group by columnName

这应该是:

select columnName, count(*) as CountOf from tableName group by columnName 

为了正确聚合 GROUP BY。