<分区>
我有:
# runPath is the current path, commands is a list that's mostly irrelevant here
def ParseShellScripts(runPath, commands):
for i in range(len(commands)):
if commands[i].startswith('{shell}'):
# todo: add validation/logging for directory `sh` and that scripts actually exist
with open(os.path.join(runPath, 'sh', commands[i][7:]),"r") as shellFile:
for matches in re.findall("/^source.*.sh", shellFile):
print matches
但是，我得到这个错误:
Traceback (most recent call last):
File "veri.py", line 396, in <module>
main()
File "veri.py", line 351, in main
servList, labels, commands, expectedResponse = ParseConfig(relativeRunPath)
File "veri.py", line 279, in ParseConfig
commands = ParseShellScripts(runPath, commands)
File "veri.py", line 288, in ParseShellScripts
for matches in re.findall("/^source.*.sh", shellFile):
File "/usr/lib/python2.7/re.py", line 177, in findall
return _compile(pattern, flags).findall(string)
TypeError: expected string or buffer
编辑: 添加一些文件作为示例
#config.sh
#!/bin/bash
dbUser = 'user'
dbPass = 'pass'
dbSchema = ''
dbMaxCons = '4000'
#the shellFile I'm looking in
#!/bin/bash
source config.sh
OUTPUT=$(su - mysql -c "mysqladmin variables" | grep max_connections | awk '{print $4}')
if [[ ${OUTPUT} -ge ${dbMaxCons}]]; then
echo "Success"
echo ${OUTPUT}
else
echo ${OUTPUT}
fi
基本上我想要完成的是搜索 sh 目录中的所有指定文件，如果其中任何一个包含 source*.sh(例如，source config.sh), 打印那个文件(最终我会把它展开并将它附加到当前文件的顶部，这样我就可以通过 ssh 传递单个命令字符串..但这不相关在这里我不认为。)
我做错了什么？