python - 在字符串中的数组中查找任何值的出现并打印它

Question

我知道这些会非常简单，但它对我不起作用。

INDICATORS = ['dog', 'cat', 'bird']
STRING_1 = 'There was a tree with a bird in it'
STRING_2 = 'The dog was eating a bone'
STRING_3 = "Rick didn't let morty have a cat"


def FindIndicators(TEXT):
    if any(x in TEXT for x in INDICATORS):
        print x # 'x' being what I hoped was whatever the match would be (dog, cat)

预期输出:

FindIndicators(STRING_1)
# bird

FindIndicators(STRING_2)
# dog

FindIndicators(STRING_3)
# cat

相反，我得到了“x”的未解决引用。我有一种感觉，我一看到答案就会去办公 table 。

Answer 1

您误解了 any() 的工作原理。它消耗你给它的任何东西并返回 True 或 False。 x 之后不存在。

>>> INDICATORS = ['dog', 'cat', 'bird']
>>> TEXT = 'There was a tree with a bird in it'
>>> [x in TEXT for x in INDICATORS]
[False, False, True]
>>> any(x in TEXT for x in INDICATORS)
True

改为这样做:

>>> for x in INDICATORS:
...     if x in TEXT:
...         print x
...
bird